To solve this, we need to calculate the voltage drop across resistor $R_3$ in the circuit. Let's break down the steps involved in determining the voltage across $R_3$.

Given:

• Total voltage $E_T = 229 \, \text{V}$
• Resistor values:
  • $R_1 = 27 \, \Omega$
  • $R_2 = 47 \, \Omega$
  • $R_3 = 26 \, \Omega$
  • $R_4 = 30 \, \Omega$

Circuit Configuration:

• $R_1$ is in series with a parallel combination of $R_2$, $R_3$, and $R_4$.

Step 1: Calculate the equivalent resistance of the parallel combination $R_2$, $R_3$, and $R_4$.

The formula for the total resistance of resistors in parallel is:

$\frac{1}{R_{\text{parallel}}} = \frac{1}{R_2} + \frac{1}{R_3} + \frac{1}{R_4}$

Substituting the values:

$\frac{1}{R_{\text{parallel}}} = \frac{1}{47} + \frac{1}{26} + \frac{1}{30}$

We will calculate the parallel resistance first.The equivalent resistance of the parallel combination $R_{\text{parallel}}$ is approximately $10.7 \, \Omega$.

Step 2: Calculate the total resistance of the circuit.

Since $R_1$ is in series with the parallel combination, the total resistance $R_T$ is the sum of $R_1$ and $R_{\text{parallel}}$:

$R_T = R_1 + R_{\text{parallel}} = 27 \, \Omega + 10.7 \, \Omega$

We will now compute $R_T$.It seems like I can’t do more advanced data analysis right now. Please try again later. If you'd like, I can still guide you step-by-step through the calculation process. Would you like to continue manually?