Use your graphing calculator to find the equation of the trend line for the scatterplot below.

x	y
1	17
2	20
3	22
4	26
5	28
6	31

To find the equation of the trend line (or line of best fit) for the given scatterplot, we can use linear regression. The formula for the equation of the line is \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept.

Let's calculate the slope \( m \) and y-intercept \( b \) using the following formulas:

\[ m = \frac{N \sum xy - (\sum x)(\sum y)}{N \sum x^2 - (\sum x)^2} \]
\[ b = \frac{\sum y - m(\sum x)}{N} \]

Where \( N \) is the number of data points.

Given dataTo find the equation of the trend line (or line of best fit) for the given scatterplot, we can use linear regression. The formula for the equation of the line is \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept.

Let's calculate the slope \( m \) and y-intercept \( b \) using the following formulas:

\[ m = \frac{N \sum xy - (\sum x)(\sum y)}{N \sum x^2 - (\sum x)^2} \]
\[ b = \frac{\sum y - m(\sum x)}{N} \]

Where \( N \) is the number of data points.

Given 

| x | y  |
|---|----|
| 1 | 17 |
| 2 | 20 |
| 3 | 22 |
| 4 | 26 |
| 5 | 28 |
| 6 | 31 |

Calculate the necessary sums:

\[ \sum x = 1 + 2 + 3 + 4 + 5 + 6 = 21 \]
\[ \sum y = 17 + 20 + 22 + 26 + 28 + 31 = 144 \]
\[ \sum xy = (1 \cdot 17) + (2 \cdot 20) + (3 \cdot 22) + (4 \cdot 26) + (

Learn how to find the equation of the trend line for a scatterplot using linear regression. Calculate the slope and y-intercept from the given data points: (1, 17), (2, 20), (3, 22), (4, 26), (5, 28), (6, 31). Suitable for high school students.

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