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The image provided contains a question regarding finding the equation of a straight line based on the given graph.

Here's a summary of the steps:

1. **Calculate the gradient of the line**:
   Two points on the line are given: (0, 4) and (2, 8).
   The gradient (slope) formula is:
   \[
   m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{8 - 4}{2 - 0} = \frac{4}{2} = 2
   \]
   So, the gradient \( m = 2 \).

2. **State the y-intercept of the straight line**:
   The y-intercept occurs when \( x = 0 \). From the point (0, 4), we see that the y-intercept is 4.

3. **Write the equation of the line in the form \( y = mx + c \)**:
   Using the gradient \( m = 2 \) and the y-intercept \( c = 4 \), the equation of the line is:
   \[
   y = 2x + 4
   \]

This is the required equation of the straight line.

Would you like any additional details or clarifications on this? Here are five relative questions:

1. How do we generalize the equation of any straight line?
2. What does the gradient represent geometrically on a graph?
3. Can you explain why the y-intercept occurs when \( x = 0 \)?
4. How would the equation change if the line had a negative gradient?
5. How do we find the x-intercept from the equation of a straight line?

**Tip**: When finding the gradient of a line, always ensure you're using two distinct points on the line and applying the formula correctly to avoid sign errors.

Work out the equation of the straight line given in the diagram below. Calculate the gradient of the line, state the y-intercept, and write the equation in the form y = mx + c.

Learn how to find the equation of a straight line by calculating the gradient and y-intercept from two given points. Suitable for students in Grades 8-10. The example uses the line passing through points (0, 4) and (2, 8).

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