Math Problem Statement
Solution
To find the equation of a plane passing through three points, , , and , we can proceed with the following steps:
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Calculate Two Direction Vectors:
- Vector from to :
- Vector from to :
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Find the Cross Product : The cross product of and will give us a vector that is perpendicular to the plane, which we can use as the normal vector .
Expanding this determinant:
So, the normal vector .
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Form the Equation of the Plane: Using the point-normal form of the plane, , where is a point on the plane (let’s use ) and :
Expanding this:
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Simplify the Equation: Divide through by 11 to simplify:
Thus, the equation of the plane passing through points , , and is:
Would you like a detailed explanation of each step or have any questions about the process?
Here are five questions to expand your understanding:
- How can the cross product of two vectors help in determining the equation of a plane?
- What would change if we used a different point on the plane in the point-normal form?
- Why is it necessary to simplify the equation after forming it initially?
- How would you confirm if a fourth point lies on the same plane?
- Can this approach be extended to higher-dimensional spaces?
Tip: Always ensure to check the result by plugging back at least one point into the final equation to verify its correctness.
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Math Problem Analysis
Mathematical Concepts
Vector Algebra
Plane Equation
Cross Product
Formulas
Vector PQ = Q - P
Vector PR = R - P
Cross Product formula for vectors
Equation of plane in point-normal form: a(x - x1) + b(y - y1) + c(z - z1) = 0
Theorems
Properties of cross products
Point-normal form of a plane equation
Suitable Grade Level
Grades 11-12
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