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The problem asks for the equation of a line in slope-intercept form that passes through a given point and is parallel to a specified line.

### Problem Details
The task is to find the slope-intercept form of a line that:
1. Passes through the point \((3, 5)\).
2. Is parallel to the line \(y = -2\).

### Solution Steps

1. **Identify the Slope of the Given Line:**
   - The line \(y = -2\) is a horizontal line, which has a slope of \(0\).
   - Since the new line is parallel to this one, it will also have a slope of \(0\).

2. **Set Up the Equation Using the Slope-Intercept Form:**
   - The slope-intercept form is \(y = mx + b\), where \(m\) is the slope.
   - Since \(m = 0\), our equation so far is:
     \[
     y = 0 \cdot x + b \Rightarrow y = b
     \]

3. **Find the Value of \(b\) Using the Given Point \((3, 5)\):**
   - Substitute \(x = 3\) and \(y = 5\) into the equation \(y = b\):
     \[
     5 = b
     \]

4. **Write the Final Equation:**
   - The equation of the line is:
     \[
     y = 5
     \]

### Answer
The slope-intercept form of the line that passes through \((3, 5)\) and is parallel to \(y = -2\) is:
\[
y = 5
\]

Would you like more details on this solution or have any questions?

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Here are some related questions you might find useful:
1. How do you find the slope of a line given two points?
2. What is the general approach for finding a line parallel to a given line?
3. How would you find a line perpendicular to a given line?
4. Can a vertical line be expressed in slope-intercept form?
5. How do you convert between different forms of linear equations?

**Tip:** For any line parallel to a given one, use the same slope and adjust only the intercept.

Write the slope-intercept form of the equation of the line described.
Through: (3, 5), parallel to y = -2

Learn how to write the slope-intercept form of a line that passes through the point (3, 5) and is parallel to y = -2. This solution covers key algebra concepts and shows how to handle parallel lines and slope-intercept equations. Suitable for students in Grades 8-10.

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