Find an equation of the line with slope m that passes through the given point (-3,-9), m=0

To find the equation of a line with a given slope \( m \) and passing through a specific point \((x_1, y_1)\), we use the point-slope form of the equation of a line:

\[
y - y_1 = m(x - x_1)
\]

Given:
- Slope \( m = 0 \)
- Point \((-3, -9)\)

Substitute the values into the point-slope form:

\[
y - (-9) = 0(x - (-3))
\]

Simplify the equation:

\[
y + 9 = 0 \times (x + 3)
\]

\[
y + 9 = 0
\]

Finally, subtract 9 from both sides to get the equation of the line:

\[
y = -9
\]

So, the equation of the line is:

\[
y = -9
\]

This is a horizontal line passing through \( y = -9 \).

Would you like any further details or have any questions?

Here are some related questions you might find helpful:
1. What is the general form of the equation of a horizontal line?
2. How do you find the equation of a vertical line passing through a given point?
3. What is the slope of a vertical line?
4. How do you find the distance between a point and a line?
5. What is the equation of a line perpendicular to a horizontal line?

**Tip:** A line with a slope of zero is always horizontal, and its equation is in the form \( y = c \), where \( c \) is the constant y-value.

Learn how to find the equation of a line with slope 0 passing through the point (-3, -9). This problem involves using the point-slope form of a line equation to determine the equation of a horizontal line. Suitable for students in Grades 7-9.

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