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To find the equation of a line that has a slope of 3 and passes through the point (-3, -5), we can use the point-slope form of the equation of a line:

\[
y - y_1 = m(x - x_1)
\]

where \( m \) is the slope and \( (x_1, y_1) \) is a point on the line.

Given:
- Slope \( m = 3 \)
- Point \( (-3, -5) \)

Plug these values into the point-slope formula:

\[
y - (-5) = 3(x - (-3))
\]

Simplify:

\[
y + 5 = 3(x + 3)
\]

Now expand the equation:

\[
y + 5 = 3x + 9
\]

Subtract 5 from both sides to get the equation in slope-intercept form:

\[
y = 3x + 4
\]

So, the correct equation is:

\[
\boxed{y = 3x + 4}
\]

Therefore, the correct answer is **option A**. 

Would you like further details or have any questions?

Here are five related questions to explore further:
1. How do you convert from point-slope form to slope-intercept form?
2. What does the slope of a line represent in a real-world context?
3. How can you find the equation of a line if two points are given instead of one?
4. How do you check if a point lies on a given line?
5. What is the effect of changing the slope of a line on its graph?

**Tip:** When given a point and a slope, always use the point-slope form first; it simplifies converting into the final equation.

What is the equation of the line that has a slope of 3 and goes through the point (-3, -5)?

Learn how to find the equation of a line that has a slope of 3 and passes through the point (-3, -5). Using the point-slope form, this problem demonstrates how to convert the equation into slope-intercept form. Suitable for students in Grades 7-9.

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