To find the equation of the line passing through the points $(-5, -3)$ and $(5, -2)$, we will use the point-slope form of the equation of a line:

1. Calculate the slope (m): The formula for the slope between two points $(x_1, y_1)$ and $(x_2, y_2)$ is: $m = \frac{y_2 - y_1}{x_2 - x_1}$ Substituting the given points $(-5, -3)$ and $(5, -2)$: $m = \frac{-2 - (-3)}{5 - (-5)} = \frac{-2 + 3}{5 + 5} = \frac{1}{10}$

2. Use the point-slope form: The point-slope form of the equation of a line is: $y - y_1 = m(x - x_1)$ Using the slope $m = \frac{1}{10}$ and one of the points $(-5, -3)$: $y - (-3) = \frac{1}{10}(x - (-5))$ Simplify: $y + 3 = \frac{1}{10}(x + 5)$ $y + 3 = \frac{1}{10}x + \frac{1}{2}$

3. Solve for $y$: $y = \frac{1}{10}x + \frac{1}{2} - 3$ $y = \frac{1}{10}x + \frac{1}{2} - \frac{6}{2}$ $y = \frac{1}{10}x - \frac{5}{2}$

Thus, the equation of the line in terms of $x$ is: $y = \frac{1}{10}x - \frac{5}{2}$

Would you like more details or have any questions?

Here are 5 questions you might ask next:

1. How do you find the equation of a line given the slope and a point?
2. What is the point-slope form of a linear equation?
3. How can I convert the point-slope form to the slope-intercept form?
4. What is the standard form of a linear equation?
5. How do you find the slope of a line given two points?

Tip: When finding the equation of a line, always start by calculating the slope, then use the point-slope form to derive the equation.