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The question asks for the equation of a straight line with a gradient (slope) of 5 that passes through the point \( (0, 3) \). The equation should be in the form:

\[
y = mx + c
\]

where \( m \) is the gradient (slope) and \( c \) is the y-intercept.

### Step-by-Step Solution:

1. **Identify the gradient \( m \):**
   - The gradient is given as \( m = 5 \).

2. **Identify the y-intercept \( c \):**
   - The line passes through the point \( (0, 3) \), which means when \( x = 0 \), \( y = 3 \). This gives the y-intercept \( c = 3 \).

3. **Form the equation:**
   Using the values of \( m \) and \( c \), we can write the equation of the line as:

   \[
   y = 5x + 3
   \]

### Final Answer:
The equation of the line is:

\[
y = 5x + 3
\]

Would you like more details on this solution or have any other questions?

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Here are 5 related questions to expand on this concept:
1. How do you find the equation of a line given two points on the line?
2. What is the relationship between the slope of a line and its angle with the x-axis?
3. How does changing the gradient affect the steepness of a line?
4. What happens to the equation if the line passes through the origin?
5. How do you find the equation of a line perpendicular to a given line?

**Tip:** To verify the equation of a line, substitute the given point into the equation and check if it satisfies the equation.

What is the equation of the straight line with gradient 5 that passes through (0, 3)?

Learn how to find the equation of a straight line with gradient 5 that passes through the point (0, 3). This problem involves the slope-intercept form (y = mx + c) and demonstrates how to determine the y-intercept from a point on the line. Suitable for students in Grades 8-10.

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