The question asks for the equation of a straight line with a gradient (slope) of 5 that passes through the point $(0, 3)$. The equation should be in the form:

$y = mx + c$

where $m$ is the gradient (slope) and $c$ is the y-intercept.

Step-by-Step Solution:

1. Identify the gradient $m$:

   • The gradient is given as $m = 5$.

2. Identify the y-intercept $c$:

   • The line passes through the point $(0, 3)$, which means when $x = 0$, $y = 3$. This gives the y-intercept $c = 3$.

3. Form the equation: Using the values of $m$ and $c$, we can write the equation of the line as:

   $y = 5x + 3$

Final Answer:

The equation of the line is:

$y = 5x + 3$

Would you like more details on this solution or have any other questions?

Here are 5 related questions to expand on this concept:

1. How do you find the equation of a line given two points on the line?
2. What is the relationship between the slope of a line and its angle with the x-axis?
3. How does changing the gradient affect the steepness of a line?
4. What happens to the equation if the line passes through the origin?
5. How do you find the equation of a line perpendicular to a given line?

Tip: To verify the equation of a line, substitute the given point into the equation and check if it satisfies the equation.