find the equation of an ellipse with center at the origin and passing through points (1,2) and (3,1).

To find the equation of an ellipse with its center at the origin and passing through the points \((1,2)\) and \((3,1)\), we follow these steps:

### Step 1: General Form of the Ellipse
The equation of an ellipse centered at the origin is given by:
\[
\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1
\]
where \(a\) and \(b\) are the semi-major and semi-minor axes, respectively.

### Step 2: Substitute the Points into the Ellipse Equation
We know the ellipse passes through the points \((1,2)\) and \((3,1)\). Substituting these into the general equation gives us two equations:

1. For the point \((1, 2)\):
\[
\frac{1^2}{a^2} + \frac{2^2}{b^2} = 1 \implies \frac{1}{a^2} + \frac{4}{b^2} = 1
\]

2. For the point \((3, 1)\):
\[
\frac{3^2}{a^2} + \frac{1^2}{b^2} = 1 \implies \frac{9}{a^2} + \frac{1}{b^2} = 1
\]

### Step 3: Solve the System of Equations
We now have the following system of equations:
\[
\frac{1}{a^2} + \frac{4}{b^2} = 1 \quad \text{(Equation 1)}
\]
\[
\frac{9}{a^2} + \frac{1}{b^2} = 1 \quad \text{(Equation 2)}
\]

To solve this system, let's multiply each equation by \(a^2b^2\) to eliminate the denominators:

From Equation 1:
\[
b^2 + 4a^2 = a^2b^2
\]

From Equation 2:
\[
9b^2 + a^2 = a^2b^2
\]

Let's now solve these equations simultaneously to find \(a^2\) and \(b^2\).

### Step 4: Eliminate \(a^2b^2\) and Solve for \(a^2\) and \(b^2\)
Subtract the first equation from the second:
\[
(9b^2 + a^2) - (b^2 + 4a^2) = 0
\]
\[
8b^2 - 3a^2 = 0
\]
\[
8b^2 = 3a^2
\]
\[
b^2 = \frac{3}{8}a^2
\]

### Step 5: Substitute Back to Find Specific Values
Substituting \(b^2 = \frac{3}{8}a^2\) into Equation 1:
\[
\frac{1}{a^2} + \frac{4}{\frac{3}{8}a^2} = 1
\]
\[
\frac{1}{a^2} + \frac{32}{3a^2} = 1
\]
\[
\frac{3 + 32}{3a^2} = 1
\]
\[
\frac{35}{3a^2} = 1
\]
\[
a^2 = \frac{35}{3}
\]

Now, substitute back to find \(b^2\):
\[
b^2 = \frac{3}{8} \times \frac{35}{3} = \frac{35}{8}
\]

### Step 6: Final Equation of the Ellipse
The equation of the ellipse is:
\[
\frac{x^2}{\frac{35}{3}} + \frac{y^2}{\frac{35}{8}} = 1
\]
This can be simplified as:
\[
\frac{8x^2}{35} + \frac{3y^2}{35} = 1
\]
or multiplying the entire equation by 35:
\[
8x^2 + 3y^2 = 35
\]

This is the equation of the ellipse.

Would you like more details or have any questions? Here are five related questions you might find helpful:

1. How do you derive the general form of an ellipse centered at a point other than the origin?
2. What are the differences between ellipses and circles in terms of their equations?
3. How do you find the foci of an ellipse?
4. Can the major axis of an ellipse be aligned with the y-axis instead of the x-axis?
5. How do the lengths of the axes affect the shape of the ellipse?

**Tip:** Remember that the general form of an ellipse is flexible and can be rotated or translated to fit different scenarios.

Learn how to find the equation of an ellipse with its center at the origin and passing through the points (1,2) and (3,1). This problem involves coordinate geometry and the equation of an ellipse, suitable for high school students.

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