Center at the origin and passes through a point (-3,4).

To find the equation of a circle centered at the origin and passing through the point \((-3, 4)\), we can use the standard equation of a circle:

\[ x^2 + y^2 = r^2 \]

Here, \((h, k)\) is the center of the circle, and \(r\) is the radius. Since the circle is centered at the origin, \((h, k) = (0, 

Learn how to find the equation of a circle centered at the origin and passing through the point (-3, 4). This problem involves using the standard equation of a circle in coordinate geometry. Suitable for high school students studying geometry.

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