Math Problem Statement
Find the distance that the object made during its 6s of moving
Solution
The graph provided shows the velocity of an object over time , where velocity is on the y-axis (in meters per second, m/s), and time is on the x-axis (in seconds, s). To find the distance traveled by the object during the 6 seconds, we need to compute the area under the velocity-time graph, as the area under this curve represents the total displacement or distance traveled.
Step-by-Step Solution:
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Analyze the graph:
- From to , the velocity increases linearly from 0 to 6 m/s.
- From to , the velocity decreases linearly from 6 m/s back to 0 m/s.
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Divide the graph into simple shapes:
- The graph forms a triangle with a base along the time axis from to and a height of 6 m/s.
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Calculate the area of the triangle: The formula for the area of a triangle is:
- Base seconds (from to )
- Height m/s (maximum velocity)
Thus, the total distance traveled by the object during the 6 seconds is 18 meters.
Would you like more details or have any questions?
Here are some related questions to deepen understanding:
- How would the result change if the graph had different shapes, such as rectangles or trapezoids?
- What does it mean physically if the graph dips below the time axis (negative velocity)?
- How would you calculate the distance if the object reversed direction halfway through the motion?
- What is the difference between distance and displacement in this context?
- How would the total distance change if the velocity was constant instead of varying?
Tip: When calculating distance from a velocity-time graph, always remember that the area under the curve (above the time axis) represents distance.
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Math Problem Analysis
Mathematical Concepts
Physics
Kinematics
Velocity-Time Graph
Displacement
Formulas
Area of a triangle = (1/2) × base × height
Theorems
The area under a velocity-time graph represents the total displacement or distance traveled.
Suitable Grade Level
Grades 8-10
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