Math Problem Statement

Find the discriminant and the number of real roots for the equation 4x^2 + 12x + 9 = 0.

Solution

The question asks to find the discriminant and the number of real roots for the quadratic equation:

4x2+12x+9=04x^2 + 12x + 9 = 0

To solve this, we use the discriminant formula, which is part of the quadratic formula:

Δ=b24ac\Delta = b^2 - 4ac

For the equation 4x2+12x+9=04x^2 + 12x + 9 = 0, the coefficients are:

  • a=4a = 4
  • b=12b = 12
  • c=9c = 9

Now, calculate the discriminant:

Δ=(12)24(4)(9)\Delta = (12)^2 - 4(4)(9) Δ=144144\Delta = 144 - 144 Δ=0\Delta = 0

Since the discriminant is 0, there is exactly one real root.

Therefore, the correct answer is A: 0; one real root.

Do you want more details on how this works or have any other questions?

Here are 5 related questions to expand on this concept:

  1. What happens if the discriminant is negative?
  2. How do you factor a quadratic equation with a discriminant of zero?
  3. Can a quadratic equation have two complex roots if the discriminant is positive?
  4. What is the geometric significance of having only one real root for a quadratic equation?
  5. How does changing the value of cc affect the number of real roots?

Tip: The discriminant is the key to quickly determining the nature of the roots of any quadratic equation.

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Equations
Discriminants

Formulas

Discriminant: Δ = b^2 - 4ac

Theorems

Quadratic formula: x = (-b ± √Δ) / 2a

Suitable Grade Level

Grades 8-10