Math Problem Statement
Find the direction cosines and direction angles of the vector. (Give the direction angles correct to the nearest degree.) <2,1,2>
Solution
The direction cosines and direction angles of a vector can be determined by first finding the magnitude of the vector, and then using it to compute the cosines of the angles between the vector and the coordinate axes. These angles are called the direction angles.
Step 1: Find the magnitude of the vector
The magnitude of the vector is given by:
Step 2: Find the direction cosines
The direction cosines are given by:
where , , and are the direction angles with respect to the -, -, and -axes, respectively.
For the vector and its magnitude :
Step 3: Find the direction angles
To find the direction angles, take the inverse cosine (arccos) of the direction cosines:
Now, calculate these values to the nearest degree:
Final Answer:
- Direction cosines: , ,
- Direction angles: , ,
Would you like further details or have any questions?
Here are some related questions:
- What are direction cosines for vectors in 2D space?
- How do you interpret direction angles geometrically?
- What is the difference between direction angles and direction cosines?
- How are direction cosines used in physics, especially in vectors in 3D space?
- What would happen to direction angles if the vector were normalized?
Tip: The direction angles always add up to less than because they are the angles between the vector and each axis, not the angles between the axes themselves.
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Math Problem Analysis
Mathematical Concepts
Vector Geometry
Direction Cosines
Direction Angles
3D Coordinate Systems
Formulas
Magnitude of a vector: |v| = sqrt(x^2 + y^2 + z^2)
Direction cosines: cos(α) = x/|v|, cos(β) = y/|v|, cos(γ) = z/|v|
Direction angles: α = cos^(-1)(x/|v|), β = cos^(-1)(y/|v|), γ = cos^(-1)(z/|v|)
Theorems
Trigonometric identities for cosines
Pythagorean theorem in 3D space
Suitable Grade Level
Grades 11-12 or early college