Math Problem Statement

ABCD is a kite with AB = AD and CB = CD A is the point with coordinates (-2, 10) B is the point with coordinates( -27/5 , 4) C is the point with coordinates (4,−5) Work out the coordinates of D

Solution

Given that ABCDABCD is a kite with AB=ADAB = AD and CB=CDCB = CD, points AA and CC are the endpoints of the kite's diagonal. In a kite, the diagonals are perpendicular bisectors of each other.

  1. Find the midpoint of diagonal ACAC:
    The midpoint MM of ACAC (where MM is also the midpoint of BDBD) is calculated by averaging the coordinates of AA and CC: M=(2+42,10+(5)2)=(22,52)=(1,2.5)M = \left(\frac{-2 + 4}{2}, \frac{10 + (-5)}{2}\right) = \left(\frac{2}{2}, \frac{5}{2}\right) = (1, 2.5)

  2. Find the slope of ACAC: The slope of ACAC is: slope of AC=5104(2)=156=52\text{slope of } AC = \frac{-5 - 10}{4 - (-2)} = \frac{-15}{6} = -\frac{5}{2}

  3. Determine the slope of BDBD: Since the diagonals of a kite are perpendicular, the slope of BDBD will be the negative reciprocal of the slope of ACAC. Thus: slope of BD=25\text{slope of } BD = \frac{2}{5}

  4. Set up the line equation for BDBD: The line BDBD passes through M=(1,2.5)M = (1, 2.5) with slope 25\frac{2}{5}. The equation of a line is y=mx+cy = mx + c. Substituting the values: y=25x+cy = \frac{2}{5}x + c Substitute MM into the equation to solve for cc: 2.5=25(1)+c2.5=25+cc=2.50.4=2.12.5 = \frac{2}{5}(1) + c \Rightarrow 2.5 = \frac{2}{5} + c \Rightarrow c = 2.5 - 0.4 = 2.1 Therefore, the equation of line BDBD is: y=25x+2.1y = \frac{2}{5}x + 2.1

  5. Find DD as the reflection of BB across MM: To find the coordinates of DD, we use the midpoint formula. Since MM is the midpoint of BB and DD: M=(275+xD2,4+yD2)=(1,2.5)M = \left(\frac{-\frac{27}{5} + x_D}{2}, \frac{4 + y_D}{2}\right) = (1, 2.5) Solving for xDx_D and yDy_D:

    • xx-coordinate: 275+xD2=1275+xD=2xD=2+275=375=7.4\frac{-\frac{27}{5} + x_D}{2} = 1 \Rightarrow -\frac{27}{5} + x_D = 2 \Rightarrow x_D = 2 + \frac{27}{5} = \frac{37}{5} = 7.4
    • yy-coordinate: 4+yD2=2.54+yD=5yD=1\frac{4 + y_D}{2} = 2.5 \Rightarrow 4 + y_D = 5 \Rightarrow y_D = 1
  6. Conclusion: The coordinates of point DD are (7.4,1)(7.4, 1).

Would you like a deeper explanation on any part of the solution?


  1. What are the properties of a kite’s diagonals in geometry?
  2. How do you calculate the midpoint between two points?
  3. Why are the diagonals of a kite perpendicular?
  4. What is the method to find the reflection point over a midpoint?
  5. How does slope influence the perpendicularity of lines?

Tip: In any quadrilateral, understanding the properties of its diagonals helps in determining unknown points or angles.

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Math Problem Analysis

Mathematical Concepts

Geometry
Coordinate Geometry
Properties of Kites
Perpendicular Bisectors
Midpoints
Slope

Formulas

Midpoint formula: M = ((x1 + x2)/2, (y1 + y2)/2)
Slope formula: m = (y2 - y1) / (x2 - x1)
Reflection point calculation over a midpoint

Theorems

Properties of Kite Diagonals
Perpendicularity of Diagonals in a Kite

Suitable Grade Level

Grades 9-10