The sum of two consecutive numbers is -161. Find the value of the greater number.

Let the two consecutive numbers be represented as \( x \) and \( x + 1 \), where \( x \) is the smaller number. According to the problem, the sum of these two numbers is -161. We can express this as the following equation:

\[
x + (x + 1) = -161
\]

Simplifying the equation:

\[
2x + 1 = -161
\]

Now, subtract 1 from both sides:

\[
2x = -162
\]

Divide both sides by 2:

\[
x = -81
\]

Since \( x \) is the smaller number, the greater number is:

\[
x + 1 = -81 + 1 = -80
\]

Thus, the value of the greater number is \( \boxed{-80} \).

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### Related questions:
1. What is the sum of two consecutive even numbers if their sum is 120?
2. How do you find two consecutive odd numbers whose sum is 100?
3. What is the equation for the sum of two consecutive numbers if their sum is \( x \)?
4. How does this method change if the sum of three consecutive numbers is given?
5. Can you find three consecutive even numbers whose sum is 180?

**Tip:** When dealing with consecutive numbers, always set one as \( x \) and express the next as \( x+1 \), \( x+2 \), etc.

Discover how to solve the problem of finding two consecutive numbers whose sum is -161. This step-by-step algebraic solution covers linear equations and consecutive integer properties, ideal for students in Grades 6-8.

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