Math Problem Statement

Time left 0:53:07 Question 1 Not yet answered Marked out of 1.00 Flag question Question text Which answer choice shows the center of the circle with the equation x2 + y2 -8x +14y +57.

Question 1Select one:

a. (4, -7)

b. (7, 4)

c. (-7, 4)

d. (-4, 7)

Question 2 Not yet answered Marked out of 1.00 Flag question Question text What is the standard form of the equation of the circle x2 + y2 + 10x - 4y - 7 = 0?

Question 2Select one:

a. (x + 5)2 + (y - 2)2 = 62

b. (x + 5)2 + (y + 2)2 = 62

c. (x - 5)2 + (y - 2)2 = 62

d. (x - 5)2 + (y + 2)2 = 62

Solution

Let's solve each question step by step.

Question 1: Finding the Center of the Circle

The equation of the circle is:

x2+y28x+14y+57=0x^2 + y^2 - 8x + 14y + 57 = 0

To find the center of the circle, we need to rewrite the equation in the standard form:

(xh)2+(yk)2=r2(x - h)^2 + (y - k)^2 = r^2

where (h,k)(h, k) is the center of the circle. We do this by completing the square for both xx and yy.

Step-by-Step Solution:

  1. Group the xx and yy terms:

(x28x)+(y2+14y)=57(x^2 - 8x) + (y^2 + 14y) = -57

  1. Complete the square for xx:

x28x(x4)216x^2 - 8x \rightarrow (x - 4)^2 - 16

  1. Complete the square for yy:

y2+14y(y+7)249y^2 + 14y \rightarrow (y + 7)^2 - 49

  1. Substitute back into the equation:

(x4)216+(y+7)249=57(x - 4)^2 - 16 + (y + 7)^2 - 49 = -57

  1. Combine constants:

(x4)2+(y+7)2=8(x - 4)^2 + (y + 7)^2 = 8

  1. Identify the center:

The center of the circle is (h,k)=(4,7)(h, k) = (4, -7).

Correct Answer for Question 1:

  • a. (4, -7)

Question 2: Converting to Standard Form

The equation of the circle is:

x2+y2+10x4y7=0x^2 + y^2 + 10x - 4y - 7 = 0

We will also rewrite this in the standard form (xh)2+(yk)2=r2(x - h)^2 + (y - k)^2 = r^2 by completing the square.

Step-by-Step Solution:

  1. Group the xx and yy terms:

(x2+10x)+(y24y)=7(x^2 + 10x) + (y^2 - 4y) = 7

  1. Complete the square for xx:

x2+10x(x+5)225x^2 + 10x \rightarrow (x + 5)^2 - 25

  1. Complete the square for yy:

y24y(y2)24y^2 - 4y \rightarrow (y - 2)^2 - 4

  1. Substitute back into the equation:

(x+5)225+(y2)24=7(x + 5)^2 - 25 + (y - 2)^2 - 4 = 7

  1. Combine constants:

(x+5)2+(y2)2=36(x + 5)^2 + (y - 2)^2 = 36

  1. Identify the correct form:

The standard form is (x+5)2+(y2)2=62(x + 5)^2 + (y - 2)^2 = 6^2.

Correct Answer for Question 2:

  • a. (x + 5)^2 + (y - 2)^2 = 62

Summary of Answers:

  1. Question 1: a. (4, -7)
  2. Question 2: a. (x + 5)^2 + (y - 2)^2 = 62

Would you like a more detailed explanation, or do you have any questions?

Related Questions to Expand Your Understanding:

  1. How do you complete the square for an equation with different coefficients?
  2. What is the geometric significance of completing the square in a circle equation?
  3. Can the center of a circle ever have negative coordinates?
  4. How do changes in the equation of a circle affect its radius and position?
  5. How do you find the radius of a circle from its standard form equation?

Tip:

Completing the square is a powerful technique to rewrite quadratic equations in a more useful form, such as finding the center and radius of a circle. Practice with different equations to become more comfortable with this process.

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Math Problem Analysis

Mathematical Concepts

Geometry
Equations of Circles
Completing the Square

Formulas

Standard form of a circle: (x - h)^2 + (y - k)^2 = r^2
Completing the square for quadratic terms: x^2 + bx -> (x + b/2)^2 - (b/2)^2

Theorems

Circle Theorem
Completing the Square

Suitable Grade Level

Grades 9-11