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Let's break down the problem step by step to find the capacity of 1 bowl:

### Given:
- 6 glasses can fill 1 jug.
- 2 glasses can fill 1 bowl.
- The total capacity of 1 glass, 1 jug, and 1 bowl is 2.97 liters.

### Let:
- \( g \) = capacity of 1 glass
- \( j \) = capacity of 1 jug
- \( b \) = capacity of 1 bowl

From the given information, we can express the capacity of the jug and the bowl in terms of the glass capacity:
- \( j = 6g \) (since 6 glasses fill 1 jug)
- \( b = 2g \) (since 2 glasses fill 1 bowl)

Now, the total capacity of 1 glass, 1 jug, and 1 bowl is 2.97 liters, so:
\[
g + j + b = 2.97
\]

Substitute \( j = 6g \) and \( b = 2g \) into this equation:
\[
g + 6g + 2g = 2.97
\]
\[
9g = 2.97
\]

Solve for \( g \) (the capacity of 1 glass):
\[
g = \frac{2.97}{9} = 0.33 \, \text{liters}
\]

Now that we know the capacity of 1 glass is 0.33 liters, we can find the capacity of 1 bowl:
\[
b = 2g = 2 \times 0.33 = 0.66 \, \text{liters}
\]

### Final Answer:
The capacity of 1 bowl is **0.66 liters**.

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Do you want more details on any part of this solution? Let me know if you have any questions.

Here are 5 related questions:
1. How would the answer change if 8 glasses were needed to fill the jug instead of 6?
2. What would be the capacity of the jug alone?
3. If the total capacity was increased to 3.5 liters, what would be the new capacity of the bowl?
4. How would you solve the problem if the number of glasses for the jug and bowl were unknown?
5. How could you check if the solution makes sense in real-life measurements?

**Tip:** When solving word problems, always express all unknown quantities in terms of one variable before solving the equations. This simplifies the process!

6 glasses can fill a jug. 2 glasses can fill a bowl. The total capacity of 1 glass, 1 jug, and 1 bowl is 2.97 liters. What is the capacity of 1 bowl?

Learn how to find the capacity of 1 bowl when given relationships between glasses, jugs, and bowls. This problem involves simple algebra and linear equations. Suitable for students in Grades 5-7.

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