Math Problem Statement

The vector x is in a subspace H with a basis Bequals​{Bold b 1​,Bold b 2​}. Find the​ B-coordinate vector of x. Bold b 1equalsleft bracket Start 2 By 1 Matrix 1st Row 1st Column 4 2nd Row 1st Column negative 15 EndMatrix right bracket ​, Bold b 2equalsleft bracket Start 2 By 1 Matrix 1st Row 1st Column negative 1 2nd Row 1st Column 5 EndMatrix right bracket ​, xequalsleft bracket Start 2 By 1 Matrix 1st Row 1st Column 4 2nd Row 1st Column negative 10 EndMatrix right bracket

Question content area bottom Part 1 left bracket Bold x right bracket Subscript Upper Bequals    enter your response here

Solution

To find the BB-coordinate vector of x\mathbf{x} relative to the basis B={b1,b2}B = \{ \mathbf{b}_1, \mathbf{b}_2 \}, we need to express x\mathbf{x} as a linear combination of b1\mathbf{b}_1 and b2\mathbf{b}_2.

That is, we want to find scalars c1c_1 and c2c_2 such that:

x=c1b1+c2b2\mathbf{x} = c_1 \mathbf{b}_1 + c_2 \mathbf{b}_2

Step 1: Set up the system of equations

The vectors b1\mathbf{b}_1, b2\mathbf{b}_2, and x\mathbf{x} are given as:

b1=[415],b2=[15],x=[410]\mathbf{b}_1 = \begin{bmatrix} 4 \\ -15 \end{bmatrix}, \quad \mathbf{b}_2 = \begin{bmatrix} -1 \\ 5 \end{bmatrix}, \quad \mathbf{x} = \begin{bmatrix} 4 \\ -10 \end{bmatrix}

We now write the equation:

[410]=c1[415]+c2[15]\begin{bmatrix} 4 \\ -10 \end{bmatrix} = c_1 \begin{bmatrix} 4 \\ -15 \end{bmatrix} + c_2 \begin{bmatrix} -1 \\ 5 \end{bmatrix}

This translates to the system of linear equations:

4=4c1c24 = 4c_1 - c_2 10=15c1+5c2-10 = -15c_1 + 5c_2

Step 2: Solve the system of equations

We solve this system step by step.

  1. From the first equation, solve for c2c_2:

c2=4c14c_2 = 4c_1 - 4

  1. Substitute this expression for c2c_2 into the second equation:

10=15c1+5(4c14)-10 = -15c_1 + 5(4c_1 - 4) 10=15c1+20c120-10 = -15c_1 + 20c_1 - 20 10+20=5c1-10 + 20 = 5c_1 10=5c110 = 5c_1 c1=2c_1 = 2

  1. Substitute c1=2c_1 = 2 back into the equation for c2c_2:

c2=4(2)4=84=4c_2 = 4(2) - 4 = 8 - 4 = 4

Step 3: Write the BB-coordinate vector

The BB-coordinate vector of x\mathbf{x} is:

[x]B=[c1c2]=[24]\left[ \mathbf{x} \right]_B = \begin{bmatrix} c_1 \\ c_2 \end{bmatrix} = \begin{bmatrix} 2 \\ 4 \end{bmatrix}

Final Answer:

[x]B=[24]\left[ \mathbf{x} \right]_B = \begin{bmatrix} 2 \\ 4 \end{bmatrix}

Would you like more details on any step or have further questions? Here are some related questions you can explore:

  1. How do you interpret the BB-coordinate vector geometrically?
  2. What is the significance of finding coordinates relative to a given basis?
  3. How do you check the solution by reconstructing x\mathbf{x}?
  4. What happens if the vectors b1\mathbf{b}_1 and b2\mathbf{b}_2 are not linearly independent?
  5. How do you calculate the BB-coordinate vector for a higher-dimensional space?

Tip: Always double-check the steps when solving linear systems to avoid arithmetic errors!

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Math Problem Analysis

Mathematical Concepts

Linear Algebra
Vector Spaces
Coordinate Vectors
Linear Combinations
Systems of Linear Equations

Formulas

x = c1 * b1 + c2 * b2

Theorems

Coordinate vector of a vector in a subspace

Suitable Grade Level

Grades 11-12