y=x^2-6x+7   The equation of the axis of the parabola is?

The equation of the axis of symmetry for a parabola in the form \( y = ax^2 + bx + c \) can be found using the formula:

\[
x = -\frac{b}{2a}
\]

For your equation \( y = x^2 - 6x + 7 \), we have:

- \( a = 1 \)
- \( b = -6 \)

Substituting these values into the formula:

\[
x = -\frac{-6}{2 \times 1} = \frac{6}{2} = 3
\]

Thus, the equation of the axis of symmetry is:

\[
x = 3
\]

Would you like more details or have any questions?

Here are 5 related questions:
1. How do you find the vertex of the parabola?
2. How do you determine if a parabola opens upward or downward?
3. What is the y-intercept of the given parabola?
4. How do you complete the square for \( y = x^2 - 6x + 7 \)?
5. What are the roots of this parabola using the quadratic formula?

**Tip:** The axis of symmetry always passes through the vertex of the parabola.

y = x^2 - 6x + 7. The equation of the axis of the parabola is?

Learn how to find the equation of the axis of symmetry for the quadratic equation y = x^2 - 6x + 7. This step-by-step guide explains key concepts such as the axis of symmetry formula and properties of quadratic functions. Suitable for students in Grades 8-10.

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