**Find the axis of symmetry for the equation:**

***y* = *x*2 + 4*x* - 6**

y = -2

x = -2

x = 2

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The equation given is:

\[ y = x^2 + 4x - 6 \]

The formula for the axis of symmetry for a quadratic equation \( y = ax^2 + bx + c \) is:

\[
x = \frac{-b}{2a}
\]

For your equation \( y = x^2 + 4x - 6 \), the values of \( a \) and \( b \) are:

- \( a = 1 \) (coefficient of \( x^2 \))
- \( b = 4 \) (coefficient of \( x \))

Now apply the formula:

\[
x = \frac{-4}{2(1)} = \frac{-4}{2} = -2
\]

So, the axis of symmetry is:

\[
x = -2
\]

Would you like more details or have any questions about this solution?

Here are 5 follow-up questions related to this topic:

1. How does the axis of symmetry help in graphing a quadratic equation?
2. What is the vertex form of a quadratic equation, and how is it useful?
3. Can you derive the vertex using the axis of symmetry for this equation?
4. What is the effect of the \( a \)-value on the orientation of a parabola?
5. How can you find the y-intercept for this quadratic equation?

**Tip:** The axis of symmetry always passes through the vertex of the parabola.

Find the axis of symmetry for the equation: y = x^2 + 4x - 6

Learn how to find the axis of symmetry for the quadratic equation y = x^2 + 4x - 6 using the formula x = -b/(2a). This guide provides a step-by-step solution with key algebraic concepts suitable for Grades 8-10.

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