I have loaded the images. Let's now calculate the areas of the two figures.

First Image (Trapezoid-like shape):

This appears to be an irregular polygon. We'll calculate its area by dividing it into simpler shapes.

1. Left side rectangle: Height = 20 cm, Width = 6 cm
2. Right side trapezoid: Two bases = 12 cm and 10 cm, Height = 6 cm.

We will add the areas of both parts to get the total.

Second Image (Irregular L-shape):

This shape can be divided into rectangles:

1. Bottom rectangle: Width = 16 cm, Height = 7 cm
2. Top-right rectangle: Width = 10 cm, Height = 8 cm

I will now proceed with calculating these areas.The areas of the two figures are as follows:

1. First Image (Irregular polygon): The total area is $186 \, \text{cm}^2$.
2. Second Image (Irregular L-shape): The total area is $192 \, \text{cm}^2$.

Would you like a breakdown of these calculations or further details? Here are some related questions for further exploration:

1. How do you find the perimeter of these shapes?
2. What are some techniques to divide irregular polygons into simpler shapes?
3. How is the formula for the area of a trapezoid derived?
4. How would scaling the dimensions of a shape affect its area?
5. What role does the Pythagorean theorem play in irregular shape decomposition?

Tip: When dealing with irregular shapes, dividing them into simpler geometric figures (rectangles, triangles, trapezoids) makes the area calculation much easier.