https://file.aiquickdraw.com/mathbot/file/1725836773323w4ep0fn2.jpg

To find the area of this irregular polygon, we can break the shape into smaller, simpler shapes (rectangles, triangles) and calculate the area of each one individually, then sum them.

Looking at the figure, it can be divided into:

1. **A large rectangle** on the left:  
   - Dimensions: 9 ft by 14 ft  
   - Area = \( 9 \, \text{ft} \times 14 \, \text{ft} = 126 \, \text{square feet} \)

2. **A smaller rectangle** on the right top:  
   - Dimensions: 3 ft by 6 ft  
   - Area = \( 3 \, \text{ft} \times 6 \, \text{ft} = 18 \, \text{square feet} \)

3. **A right triangle** on the bottom right:  
   - Base: 9 ft (horizontal length)  
   - Height: 6 ft (vertical length)  
   - Area = \( \frac{1}{2} \times 9 \, \text{ft} \times 6 \, \text{ft} = 27 \, \text{square feet} \)

### Total Area:
Now, sum the areas of the three parts:

\[
\text{Total Area} = 126 \, \text{sq ft} + 18 \, \text{sq ft} + 27 \, \text{sq ft} = 171 \, \text{square feet}
\]

Thus, the total area of the figure is **171 square feet**.

Would you like a more detailed breakdown, or do you have any questions?

Here are some related questions to expand on this:
1. How do you calculate the area of a trapezoid?
2. What are the different ways to decompose irregular shapes into simpler shapes?
3. How does the Pythagorean theorem relate to calculating the area of triangles?
4. How would you calculate the perimeter of this figure?
5. What are the formulas for the area of polygons, like parallelograms or trapezoids?

**Tip:** When working with irregular shapes, dividing them into rectangles and triangles makes calculating areas simpler.

Learn how to calculate the area of an irregular polygon by decomposing it into simpler shapes like rectangles and triangles. This problem demonstrates key geometry concepts and uses basic area formulas. Suitable for students in Grades 6-8.

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