The problem in the image asks to determine the area of two irregular shapes. These shapes are made up of a combination of rectangles, triangles, and trapezoids. Let me guide you through the process of calculating the area for each of these shapes.

Shape 1 (Left)

1. Step 1: Divide the shape into simpler shapes:

   • The shape can be split into two rectangles and one triangle.
     • A large rectangle at the bottom (8 cm by 5 cm).
     • A smaller rectangle on the top left (2 cm by 2 cm).
     • A right triangle on the top right with a base of 6 cm and a height of 2 cm.

2. Step 2: Calculate the area of each part:

   • Area of the large rectangle: $A_1 = 8 \, \text{cm} \times 5 \, \text{cm} = 40 \, \text{cm}^2$.
   • Area of the small rectangle: $A_2 = 2 \, \text{cm} \times 2 \, \text{cm} = 4 \, \text{cm}^2$.
   • Area of the triangle: $A_3 = \frac{1}{2} \times 6 \, \text{cm} \times 2 \, \text{cm} = 6 \, \text{cm}^2$.

3. Step 3: Add the areas: $\text{Total Area of Shape 1} = A_1 + A_2 + A_3 = 40 + 4 + 6 = 50 \, \text{cm}^2$

Shape 2 (Right)

1. Step 1: Divide the shape into simpler shapes:

   • The shape can be split into two trapezoids.
     • A top trapezoid with parallel sides of 4 cm and 2 cm and a height of 2 cm.
     • A bottom trapezoid with parallel sides of 8 cm and 4 cm and a height of 5 cm.

2. Step 2: Calculate the area of each trapezoid:

   • Area of the top trapezoid: $A_4 = \frac{1}{2} \times (4 \, \text{cm} + 2 \, \text{cm}) \times 2 \, \text{cm} = 6 \, \text{cm}^2$.
   • Area of the bottom trapezoid: $A_5 = \frac{1}{2} \times (8 \, \text{cm} + 4 \, \text{cm}) \times 5 \, \text{cm} = 30 \, \text{cm}^2$.

3. Step 3: Add the areas: $\text{Total Area of Shape 2} = A_4 + A_5 = 6 + 30 = 36 \, \text{cm}^2$

Final Answer:

• Area of Shape 1: $50 \, \text{cm}^2$
• Area of Shape 2: $36 \, \text{cm}^2$

Let me know if you'd like further details