Math Problem Statement

In a trapezium ABCD, AB || DC, AB = AD, ∠ADC = 64° and ∠BCD = 54°. Find ∠DBC. (a) 64° (b) 72° (c) 94° (d) 116° ( here DB is the diagonal)

Solution

We are tasked with finding DBC\angle DBC in the trapezium ABCDABCD with the given conditions:

  1. ABDCAB \parallel DC, so ABAB and DCDC are parallel.
  2. AB=ADAB = AD, so ABD\triangle ABD is isosceles.
  3. ADC=64\angle ADC = 64^\circ and BCD=54\angle BCD = 54^\circ.

Step 1: Properties of a Trapezium

In ADC\triangle ADC:

  • The interior angles sum to 180180^\circ, so: CAD+ADC+ACD=180.\angle CAD + \angle ADC + \angle ACD = 180^\circ. Since ADC=64\angle ADC = 64^\circ and ACD=BCD=54\angle ACD = \angle BCD = 54^\circ (corresponding angles due to ABDCAB \parallel DC): CAD=1806454=62.\angle CAD = 180^\circ - 64^\circ - 54^\circ = 62^\circ.

Step 2: Analyze ABD\triangle ABD

  • AB=ADAB = AD, so ABD\triangle ABD is isosceles with CAD=62\angle CAD = 62^\circ.
  • Therefore, DAB=DBA\angle DAB = \angle DBA.

Using the angle sum property in ABD\triangle ABD: DAB+DBA+ADB=180.\angle DAB + \angle DBA + \angle ADB = 180^\circ. Here, DAB=DBA\angle DAB = \angle DBA and ADB=64\angle ADB = 64^\circ: 2DAB+64=180.2\angle DAB + 64^\circ = 180^\circ. 2DAB=116DAB=58.2\angle DAB = 116^\circ \quad \Rightarrow \quad \angle DAB = 58^\circ.

Thus, DBA=58\angle DBA = 58^\circ.

Step 3: Find DBC\angle DBC

Finally, in DBC\triangle DBC:

  • BCD=54\angle BCD = 54^\circ, and DBC\angle DBC is the required angle.
  • Using the angle sum property in DBC\triangle DBC: DBC+BCD+DCB=180.\angle DBC + \angle BCD + \angle DCB = 180^\circ. Here, DCB=DBA=58\angle DCB = \angle DBA = 58^\circ (as ABD\triangle ABD and DBC\triangle DBC share diagonal DBDB): DBC+54+58=180.\angle DBC + 54^\circ + 58^\circ = 180^\circ. DBC=180112=72.\angle DBC = 180^\circ - 112^\circ = 72^\circ.

Final Answer:

(b)  72.\boxed{(b) \; 72^\circ.}

Let me know if you need further clarifications!

5 Related Questions:

  1. How do corresponding angles work in parallel lines within a trapezium?
  2. Can we determine the length of ABAB or DCDC with this data?
  3. How would the problem change if ABADAB \neq AD?
  4. Can you find ADB\angle ADB directly from other properties of trapezium?
  5. How does the sum of angles in a triangle help in such problems?

Tip:

Always double-check relationships like parallel lines or equal sides when working with trapeziums; these often simplify complex angle calculations.

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Math Problem Analysis

Mathematical Concepts

Geometry
Properties of trapeziums
Angle sum property of triangles
Isosceles triangles

Formulas

Angle sum property of a triangle: ∠A + ∠B + ∠C = 180°

Theorems

Angle properties of trapeziums
Properties of isosceles triangles

Suitable Grade Level

Grades 9-10