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The sequence given is:  
\[ 1, 4, \frac{2}{3}, 9, \frac{1}{3}, 16, \dots \]

We need to find the 11th term in this sequence.

First, let's break down the sequence to identify any patterns.

The first term is \(1\), the second term is \(4\), the third term is \(\frac{2}{3}\), the fourth term is \(9\), the fifth term is \(\frac{1}{3}\), and the sixth term is \(16\). We can see that every second term follows a different pattern.

It seems like the terms in odd positions are perfect squares:  
1st term: \(1^2 = 1\),  
3rd term: \(\frac{2}{3}\),  
5th term: \(\frac{1}{3}\),  
7th term (likely): \(\frac{2}{9}\) (following the fractional pattern).

Meanwhile, the terms in even positions are squares of integers:  
2nd term: \(2^2 = 4\),  
4th term: \(3^2 = 9\),  
6th term: \(4^2 = 16\),  
So the 8th term should be \(5^2 = 25\).

Thus, continuing this pattern, we can determine that the 11th term falls in the sequence of odd-positioned terms, so let's predict it using the fractional pattern.

Let me calculate and confirm the exact values for the 11th term.The 11th term in the sequence is approximately \( \frac{2}{27} \). 

This follows the pattern observed in the odd-positioned terms, where the fractions decrease progressively.

Would you like any further clarifications or details on the steps?

Here are 5 related questions to explore:

1. How can you determine the general formula for each set of terms (odd and even)?
2. What is the 15th term in this sequence?
3. Can you identify the sum of the first 10 terms of this sequence?
4. How do you recognize patterns in mixed sequences like this one?
5. Can you deduce the 20th term based on these patterns?

**Tip**: When dealing with sequences, always try to check patterns separately for odd and even positions to identify different progressions!

Find the 11th term in the sequence: 1, 4, 2/3, 9, 1/3, 16...

Learn how to find the 11th term in a sequence by identifying patterns in odd and even positioned terms. The sequence includes terms like 1, 4, 2/3, and more. Suitable for students in Grades 7-9.

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