To find the 11th term of a geometric sequence, we use the formula for the nth term of a geometric sequence:

$a_n = a_1 \cdot r^{(n-1)}$

Where:

• $a_n$ is the nth term.
• $a_1$ is the first term.
• $r$ is the common ratio.
• $n$ is the term number.

In the sequence $-17, -17, -17, \dots$, we observe that all terms are identical. This implies that the common ratio ($r$) is 1, as each term is multiplied by 1 to get the next term.

Thus, the formula simplifies to:

$a_{11} = -17 \cdot 1^{(11-1)} = -17 \cdot 1 = -17$

So, the 11th term is $-17$.

Would you like further explanation or have any other questions?

Here are 5 related questions to expand your understanding:

1. How do you find the common ratio in a geometric sequence?
2. What happens if the common ratio in a geometric sequence is negative?
3. How do you find the sum of the first n terms of a geometric sequence?
4. What is the formula for the sum of an infinite geometric series?
5. How do you differentiate between an arithmetic and a geometric sequence?

Tip: In a geometric sequence, if all terms are identical, the common ratio is always 1.