The expression for the $n^{th}$ term of the sequence is given as $5n$.

To find the $11^{th}$ term, substitute $n = 11$ into the formula:

$T_{11} = 5 \times 11 = 55$

So, the 11th term of the sequence is 55.

Would you like further details or have any questions?

Here are some related questions you might find helpful:

1. What is the 20th term of this sequence?
2. How do you derive the general formula for an arithmetic sequence?
3. What is the common difference in this arithmetic sequence?
4. How can you find the sum of the first $n$ terms of this sequence?
5. How would the formula change if the common difference was 7 instead of 5?

Tip: For linear sequences, the formula for the nth term is often of the form $an + b$, where $a$ is the common difference.