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The problem asks to calculate the speed of the fighter jet just before it decelerates to a complete stop after covering a distance of **44.2 m**, knowing that it initially stopped after traveling **197.4 m** at a speed of **70.4 m/s**.

We can approach this using the equation of motion, specifically:

\[
v^2 = u^2 + 2as
\]

Where:
- \( v \) is the final velocity (which is zero, since it stops completely after 197.4 m),
- \( u \) is the initial velocity (70.4 m/s),
- \( a \) is the acceleration (which we will find),
- \( s \) is the distance (197.4 m in the first case and 44.2 m in the second).

### Step 1: Calculate the acceleration
For the first part of the motion (stopping over 197.4 m), the final velocity \( v = 0 \) m/s, and the initial velocity \( u = 70.4 \) m/s. Using the equation:

\[
0 = (70.4)^2 + 2 \cdot a \cdot 197.4
\]

\[
a = \frac{-(70.4)^2}{2 \cdot 197.4}
\]

Let’s calculate the value of \( a \):

\[
a = \frac{-4956.16}{394.8} = -12.55 \, \text{m/s}^2
\]

So, the acceleration is \( a = -12.55 \, \text{m/s}^2 \).

### Step 2: Calculate the speed after traveling 44.2 m
Now, using the same equation of motion to find the speed before it covers the final **44.2 m**. We need to find the initial velocity for this part. The equation becomes:

\[
v^2 = u^2 + 2as
\]

Where:
- \( s = 44.2 \, \text{m} \),
- \( a = -12.55 \, \text{m/s}^2 \),
- \( u \) is what we need to find (the initial speed before the deceleration),
- \( v = 0 \, \text{m/s} \) (since it stops).

Rearranging the equation:

\[
0 = u^2 + 2(-12.55)(44.2)
\]

\[
u^2 = -2 \cdot (-12.55) \cdot 44.2 = 1108.82
\]

\[
u = \sqrt{1108.82} = 33.3 \, \text{m/s}
\]

Thus, the speed of the jet before traveling the last **44.2 m** is approximately **33.3 m/s**.

---

Would you like further clarification or details on this solution? Here are some related questions for further practice:

1. What is the total time taken for the jet to come to a stop from 70.4 m/s?
2. What would the deceleration be if the jet stopped over a distance of 300 meters instead?
3. How would the initial speed change if the stopping distance were doubled?
4. How much time does the jet take to reduce its speed from 33.3 m/s to zero over the final 44.2 meters?
5. Can you derive a formula for the distance covered during a deceleration from any speed to rest?

**Tip:** Always keep track of your signs when dealing with acceleration and deceleration, as confusion can lead to errors!

A fighter jet lands on an aircraft carrier at a speed of 70.4 m/s and stops after 197.4 m. What is the jet's speed before covering the final 44.2 m?

Learn how to calculate the speed of a fighter jet before it decelerates over a final distance of 44.2 m, given an initial speed of 70.4 m/s and a stopping distance of 197.4 m. This problem uses kinematic equations of motion.

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