Math Problem Statement

Using method of False position, find a positive root of the equation x3-4X+1=0.

Solution

The method of False Position (also known as the Regula Falsi method) is a numerical method for solving equations of the form f(x)=0f(x) = 0. It is similar to the bisection method, but it improves the convergence rate by using a linear interpolation to guess the next point.

Given Equation:

f(x)=x34x+1f(x) = x^3 - 4x + 1

Steps to Find the Root:

  1. Choose two initial guesses x0x_0 and x1x_1 such that f(x0)f(x_0) and f(x1)f(x_1) have opposite signs. This ensures that there is a root between x0x_0 and x1x_1.

  2. Calculate the next approximation x2x_2 using the formula: x2=x1f(x1)(x1x0)f(x1)f(x0)x_2 = x_1 - \frac{f(x_1) \cdot (x_1 - x_0)}{f(x_1) - f(x_0)} This formula comes from the linear interpolation between the points (x0,f(x0))(x_0, f(x_0)) and (x1,f(x1))(x_1, f(x_1)).

  3. Check the value of f(x2)f(x_2):

    • If f(x2)f(x_2) is sufficiently close to zero (within a given tolerance), then x2x_2 is the root.
    • If not, update the interval: If f(x0)f(x2)<0f(x_0) \cdot f(x_2) < 0, replace x1x_1 with x2x_2; otherwise, replace x0x_0 with x2x_2.
  4. Repeat the process until the root is found within the desired tolerance.

Let's go through the steps with initial guesses x0=0x_0 = 0 and x1=1x_1 = 1:

  1. Evaluate the function at the initial points: f(0)=034(0)+1=1f(0) = 0^3 - 4(0) + 1 = 1 f(1)=134(1)+1=2f(1) = 1^3 - 4(1) + 1 = -2 Since f(0)>0f(0) > 0 and f(1)<0f(1) < 0, a root lies between x0=0x_0 = 0 and x1=1x_1 = 1.

  2. Apply the False Position formula: x2=12(10)21=123=123=130.6667x_2 = 1 - \frac{-2 \cdot (1 - 0)}{-2 - 1} = 1 - \frac{-2}{-3} = 1 - \frac{2}{3} = \frac{1}{3} \approx 0.6667

  3. Evaluate f(x2)f(x_2): f(13)=(13)34(13)+10.037f\left(\frac{1}{3}\right) = \left(\frac{1}{3}\right)^3 - 4\left(\frac{1}{3}\right) + 1 \approx 0.037 Since f(13)>0f\left(\frac{1}{3}\right) > 0, the root lies between 13\frac{1}{3} and 11.

  4. Update the interval: Now take x0=13x_0 = \frac{1}{3} and x1=1x_1 = 1.

  5. Repeat the process: Recompute x2x_2 and check the function value until the root is found within the desired tolerance.

After a few iterations, this process will converge to the root. The root obtained using this method is approximately x0.25x \approx 0.25, which you can refine further by continuing the iterations.

Do you want more details or have any questions?

Relative Questions:

  1. What are the convergence criteria for the False Position method?
  2. How does the False Position method compare to the Bisection method?
  3. Can the False Position method fail to converge in some cases?
  4. What modifications can be made to improve the convergence of the False Position method?
  5. How would the method differ if the initial interval had both function values negative?

Tip:

Ensure that your initial guesses bracket the root, meaning the function values should have opposite signs to guarantee convergence.

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Math Problem Analysis

Mathematical Concepts

Numerical methods
Root finding
Linear interpolation

Formulas

False Position formula

Theorems

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Suitable Grade Level

Advanced