Math Problem Statement

factorize: 3a^4 + 2a^2 b^2 - b^4

Solution

The expression to factorize is 3a4+2a2b2b43a^4 + 2a^2b^2 - b^4.

Let's factorize it step by step:

  1. Rewrite the expression in a form that makes it easier to factor: 3a4+2a2b2b4=(3a4+2a2b2b4)3a^4 + 2a^2b^2 - b^4 = (3a^4 + 2a^2b^2 - b^4)

  2. Recognize this as a quadratic in terms of a2a^2. Let x=a2x = a^2, so the expression becomes: 3x2+2xb2b43x^2 + 2xb^2 - b^4

  3. Now, factorize the quadratic expression: 3x2+2xb2b4=(3xb2)(x+b2)3x^2 + 2xb^2 - b^4 = (3x - b^2)(x + b^2)

  4. Substitute x=a2x = a^2 back into the factors: (3a2b2)(a2+b2)(3a^2 - b^2)(a^2 + b^2)

So, the factorized form of 3a4+2a2b2b43a^4 + 2a^2b^2 - b^4 is: (3a2b2)(a2+b2)(3a^2 - b^2)(a^2 + b^2)

Would you like more details or have any questions about this factorization?

Here are 5 related questions for further exploration:

  1. How do you factorize a quadratic expression?
  2. What are the common factorization techniques for polynomials?
  3. How do you recognize if a polynomial can be factored into simpler terms?
  4. What is the difference between factorizing over real numbers versus complex numbers?
  5. Can the expression a2+b2a^2 + b^2 be further factorized over complex numbers?

Tip: When factorizing expressions, it's helpful to look for patterns, such as recognizing quadratics or special identities like difference of squares.

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Math Problem Analysis

Mathematical Concepts

Algebra
Polynomials
Factorization

Formulas

Difference of squares

Theorems

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Suitable Grade Level

Grades 10-12