Math Problem Statement

Find the factor of this perfect square trinomials

Solution

The given expression in the image is:

436u+81u24 - 36u + 81u^2

To factorize this trinomial, we need to check if it is a perfect square trinomial. A perfect square trinomial is of the form (ax+b)2=a2x2+2abx+b2(ax + b)^2 = a^2x^2 + 2abx + b^2.

  1. Rewriting the expression:

436u+81u24 - 36u + 81u^2

Let's rearrange it in standard quadratic form:

81u236u+481u^2 - 36u + 4

  1. Identify aa, bb, and cc:

a2=81u2a=9ua^2 = 81u^2 \Rightarrow a = 9u c2=4c=2c^2 = 4 \Rightarrow c = 2

  1. Check the middle term:

2ab=2(9u)(2)=36u2ab = 2(9u)(2) = 36u

Since the middle term is 36u-36u, we see that the given trinomial can indeed be written as a perfect square trinomial with a negative middle term:

81u236u+4=(9u2)281u^2 - 36u + 4 = (9u - 2)^2

Therefore, the factorization of the given perfect square trinomial is:

(9u2)2(9u - 2)^2

Would you like further details on the steps or have any other questions?

Relative Questions:

  1. What makes a trinomial a perfect square?
  2. How do you identify if a trinomial is a perfect square?
  3. Can you factorize a perfect square trinomial with a positive middle term?
  4. What are the steps to factorize a non-perfect square trinomial?
  5. How does the rearrangement of terms help in identifying a perfect square trinomial?
  6. Can you provide examples of other perfect square trinomials?
  7. How can you verify the factorization of a trinomial?
  8. What role does the middle term play in a perfect square trinomial?

Tip:

Always check the middle term to confirm if a trinomial is a perfect square. It should be twice the product of the square roots of the first and last terms.

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Math Problem Analysis

Mathematical Concepts

Quadratic Equations
Perfect Square Trinomials
Factoring

Formulas

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Theorems

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Suitable Grade Level

Grades 9-12