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The given expression is \( a^2 - 144 \). This is a difference of squares, which can be factored using the formula:

\[
x^2 - y^2 = (x - y)(x + y)
\]

In this case, \( a^2 \) is the square of \( a \), and \( 144 \) is the square of \( 12 \), since \( 12^2 = 144 \). Applying the difference of squares formula:

\[
a^2 - 144 = (a - 12)(a + 12)
\]

So, the factorization of \( a^2 - 144 \) is:

\[
(a - 12)(a + 12)
\]

Would you like more details or have any questions?

Here are 5 related questions for further practice:
1. How would you factor \( b^2 - 49 \)?
2. Can you factor \( x^2 - 25 \)?
3. What is the factorization of \( 9y^2 - 81 \)?
4. Can you factor \( 16m^2 - 1 \)?
5. How would you handle \( z^2 - 196 \)?

**Tip**: The difference of squares pattern is useful when both terms are perfect squares. Always check for this pattern when factoring.

Learn how to factorize the algebraic expression a^2 - 144 using the difference of squares method. This problem covers key concepts in algebra and is suitable for students in Grades 8-10.

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