Math Problem Statement

factor 4x23x\sqrt{4x^2-3x}

Solution

To factor the expression 4x23x\sqrt{4x^2 - 3x}, we should first focus on factoring the expression under the square root, which is 4x23x4x^2 - 3x.

Step 1: Factor 4x23x4x^2 - 3x

The common factor in 4x24x^2 and 3x-3x is xx. Thus, we can factor out xx:

4x23x=x(4x3)4x^2 - 3x = x(4x - 3)

Step 2: Apply the square root

Now we take the square root of both sides:

4x23x=x(4x3)\sqrt{4x^2 - 3x} = \sqrt{x(4x - 3)}

This can be expressed as:

4x23x=x4x3\sqrt{4x^2 - 3x} = \sqrt{x} \cdot \sqrt{4x - 3}

So, the factored form of 4x23x\sqrt{4x^2 - 3x} is:

x4x3\boxed{\sqrt{x} \cdot \sqrt{4x - 3}}

Let me know if you'd like more details or have any questions!

Here are 5 related questions:

  1. How do you factor quadratic expressions generally?
  2. What is the difference between factoring and simplifying an expression?
  3. How do you handle square roots in algebraic expressions?
  4. What is the importance of factoring in solving equations?
  5. Can every polynomial be factored?

Tip: Always look for common factors first when factoring an expression.

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Math Problem Analysis

Mathematical Concepts

Algebra
Factoring
Square Roots

Formulas

Factoring: ax^2 + bx = x(ax + b)
Square Root Property: \( \sqrt{ab} = \sqrt{a} \cdot \sqrt{b} \)

Theorems

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Suitable Grade Level

Grades 9-10