Math Problem Statement

(9x 2 −16) (6x 2 +17x+12)×(4x 2 +11x+6) ​ ÷ (8x 2 +26x+15) (2x 2 +5x−3) ​

Solution

The given expression is:

(9x216)(6x2+17x+12)(4x2+11x+6)(8x2+26x+15)(2x2+5x3)\frac{(9x^2 - 16)(6x^2 + 17x + 12)(4x^2 + 11x + 6)}{(8x^2 + 26x + 15)(2x^2 + 5x - 3)}

Step-by-Step Approach:

  1. Factor the Quadratics:
    • Let's try factoring the quadratic expressions in both the numerator and the denominator, if possible.

1. Factor 9x2169x^2 - 16 (difference of squares):

9x216=(3x4)(3x+4)9x^2 - 16 = (3x - 4)(3x + 4)

2. Factor 6x2+17x+126x^2 + 17x + 12:

We need two numbers that multiply to 6×12=726 \times 12 = 72 and add up to 1717. These are 99 and 88. So, we can factor this as: 6x2+17x+12=(2x+3)(3x+4)6x^2 + 17x + 12 = (2x + 3)(3x + 4)

3. Factor 4x2+11x+64x^2 + 11x + 6:

We need two numbers that multiply to 4×6=244 \times 6 = 24 and add up to 1111. These are 88 and 33. So, we can factor this as: 4x2+11x+6=(x+2)(4x+3)4x^2 + 11x + 6 = (x + 2)(4x + 3)

4. Factor 8x2+26x+158x^2 + 26x + 15:

We need two numbers that multiply to 8×15=1208 \times 15 = 120 and add up to 2626. These are 1010 and 1212. So, we can factor this as: 8x2+26x+15=(4x+5)(2x+3)8x^2 + 26x + 15 = (4x + 5)(2x + 3)

5. Factor 2x2+5x32x^2 + 5x - 3:

We need two numbers that multiply to 2×3=62 \times -3 = -6 and add up to 55. These are 66 and 1-1. So, we can factor this as: 2x2+5x3=(2x1)(x+3)2x^2 + 5x - 3 = (2x - 1)(x + 3)

Step 2: Simplify the Expression

Now substitute all the factored forms into the expression:

(3x4)(3x+4)(2x+3)(3x+4)(x+2)(4x+3)(4x+5)(2x+3)(2x1)(x+3)\frac{(3x - 4)(3x + 4)(2x + 3)(3x + 4)(x + 2)(4x + 3)}{(4x + 5)(2x + 3)(2x - 1)(x + 3)}

Step 3: Cancel Common Terms

  • The factor (3x+4)(3x + 4) appears twice in the numerator and once in the denominator, so we can cancel it out.
  • The factor (2x+3)(2x + 3) appears once in the numerator and once in the denominator, so we can cancel it out as well.

After canceling, we are left with:

(3x4)(x+2)(4x+3)(4x+5)(2x1)(x+3)\frac{(3x - 4)(x + 2)(4x + 3)}{(4x + 5)(2x - 1)(x + 3)}

Final Simplified Expression:

(3x4)(x+2)(4x+3)(4x+5)(2x1)(x+3)\frac{(3x - 4)(x + 2)(4x + 3)}{(4x + 5)(2x - 1)(x + 3)}


Would you like further clarification or additional steps on this? Feel free to ask!

Additional Questions:

  1. How do you factor different types of quadratic expressions efficiently?
  2. What happens if the given expression has a higher degree polynomial—how do we approach factoring?
  3. Could the cancellation process be impacted if the expression was in a different form, like involving cubes?
  4. How do you check if the factorization is correct?
  5. What are some real-life applications where simplifying rational expressions is useful?

Tip:

When factoring quadratics, always check for common patterns like difference of squares, perfect square trinomials, or use factoring by grouping for more complex trinomials.

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Math Problem Analysis

Mathematical Concepts

Algebra
Factoring Quadratic Expressions
Rational Expressions

Formulas

Difference of Squares
Factoring Quadratics
Simplifying Rational Expressions

Theorems

Factor Theorem
Difference of Squares

Suitable Grade Level

Grades 9-11