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The expression to factor is \( 225a^2 - 36b^2 \).

This is a **difference of squares** since both terms, \( 225a^2 \) and \( 36b^2 \), are perfect squares. The difference of squares formula is:

\[
x^2 - y^2 = (x - y)(x + y)
\]

First, express each term as a square:

- \( 225a^2 = (15a)^2 \)
- \( 36b^2 = (6b)^2 \)

Now, apply the difference of squares formula:

\[
225a^2 - 36b^2 = (15a - 6b)(15a + 6b)
\]

Thus, the factored form of \( 225a^2 - 36b^2 \) is:

\[
(15a - 6b)(15a + 6b)
\]

Would you like further explanation or details about the factoring process?

Here are 5 related questions:
1. How can the difference of squares formula be derived?
2. Can any polynomial with two terms be factored using difference of squares?
3. How do you recognize perfect squares in polynomial expressions?
4. What is the general method for factoring quadratic expressions?
5. How would you factor an expression like \( 225a^2 + 36b^2 \)?

**Tip:** Always check for common factors before factoring a difference of squares, as simplifying first can make the process easier.

Learn how to factor the algebraic expression 225a^2 - 36b^2 using the difference of squares formula. This problem involves recognizing perfect squares and applying the factorization technique. Suitable for students in Grades 8-10.

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