Math Problem Statement

there are two circles the distance between their middle points are 26cm. the big one radius is 15cm and small one radius is 11cm please solve external tangent

Solution

To solve for the length of the external tangent between two circles, we can use the formula:

L=d2(r1+r2)2L = \sqrt{d^2 - (r_1 + r_2)^2}

where:

  • dd is the distance between the centers of the two circles,
  • r1r_1 and r2r_2 are the radii of the circles.

Given Values:

  • d=26d = 26 cm
  • Radius of the larger circle, r1=15r_1 = 15 cm
  • Radius of the smaller circle, r2=11r_2 = 11 cm

Step-by-Step Solution:

  1. Sum of the Radii: r1+r2=15+11=26 cmr_1 + r_2 = 15 + 11 = 26 \text{ cm}

  2. Substitute in the Formula: Since d=26d = 26 cm and r1+r2=26r_1 + r_2 = 26 cm: L=262262=0=0L = \sqrt{26^2 - 26^2} = \sqrt{0} = 0

Conclusion:

The length of the external tangent LL is 00 cm, meaning that the circles are just touching externally, so no external tangent exists that would form a segment between them.

Would you like more details on why the external tangent length is zero in this case, or have any further questions?

Here are five related questions that may deepen understanding:

  1. What happens to the external tangent if the circles are separated by a larger distance?
  2. How would we calculate the internal tangent if needed?
  3. How does the distance between centers affect tangent properties?
  4. How would this change if one circle was inside the other?
  5. Can we generalize this method to circles of any radius and separation?

Tip: For any two circles that touch externally, the external tangent length is zero because they intersect at exactly one point.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Geometry
Circle Geometry
Tangents between Circles

Formulas

External Tangent Length Formula: L = √(d^2 - (r1 + r2)^2)

Theorems

Tangents to Circles Theorem

Suitable Grade Level

Grades 10-12