Let p(x)=6+9x1/2+6x+15x3/2∈P3/2
having standard ordered basis {1,x1/2,x,x3/2}

Let [I]p(x)=⎡⎣⎢⎢⎢⎢⎢⎢⎢⎢a1a2a3a4a5a6⎤⎦⎥⎥⎥⎥⎥⎥⎥⎥

Then a1+a2+a3+a4+a5+a6=

Given the polynomial \( p(x) = 6 + 9x^{1/2} + 6x + 15x^{3/2} \), we need to express it in terms of the standard ordered basis \( \{1, x^{1/2}, x, x^{3/2}\} \).

In this context:

- The coefficient of \( 1 \) is \( 6 \).
- The coefficient of \(

Learn how to express the polynomial p(x) = 6 + 9x^(1/2) + 6x + 15x^(3/2) in terms of the standard ordered basis {1, x^(1/2), x, x^(3/2)}. Understand the coefficients and their representation in linear algebra. Suitable for advanced mathematics enthusiasts.

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