Math Problem Statement

Use the variable u for the inside function to express each of the following as a composite function. ( a) y = (8t ^ 2 - 5) ^ 2 NOTE: u(t) is the inside function and y(u) is the outside function. u(t) = y (u) = ( b ) P = 8e ^ (-0.5t) NOTE: u(t) is the inside function and P(u) is the outside function . u(t) =; P(u) = C 5 ( y^ 6 +7)

Solution

Let's break down each problem and express them as composite functions, using u(t)u(t) for the inside function and either y(u)y(u) or P(u)P(u) for the outside function.

(a) y=(8t25)2y = (8t^2 - 5)^2

Here, we want to express this equation as a composite function. The inside function is what is inside the outermost operation (in this case, the squaring operation).

  • Inside function u(t)u(t): This will be the expression inside the square function.
    u(t)=8t25u(t) = 8t^2 - 5

  • Outside function y(u)y(u): This represents the squaring operation applied to the inside function.
    y(u)=u2y(u) = u^2

(b) P=8e0.5tP = 8e^{-0.5t}

Here, the goal is again to express the equation as a composite function. The inside function is what is inside the exponential function.

  • Inside function u(t)u(t): The exponent is the inside function.
    u(t)=0.5tu(t) = -0.5t

  • Outside function P(u)P(u): The outer function is the exponential operation multiplied by 8.
    P(u)=8euP(u) = 8e^u

(c) C=5(y6+7)C = 5(y^6 + 7)

Here, we need to express the equation for CC as a composite function with u(y)u(y) as the inside function and C(u)C(u) as the outside function.

  • Inside function u(y)u(y): This is the expression inside the function applied to 5.
    u(y)=y6+7u(y) = y^6 + 7

  • Outside function C(u)C(u): The outer function is multiplying by 5.
    C(u)=5uC(u) = 5u

Summary:

  1. (a)
    u(t)=8t25,y(u)=u2u(t) = 8t^2 - 5, \quad y(u) = u^2

  2. (b)
    u(t)=0.5t,P(u)=8euu(t) = -0.5t, \quad P(u) = 8e^u

  3. (c)
    u(y)=y6+7,C(u)=5uu(y) = y^6 + 7, \quad C(u) = 5u

Would you like further details or clarification?


Here are 5 related questions to expand on these concepts:

  1. How would you find the derivative of y=(8t25)2y = (8t^2 - 5)^2 using the chain rule?
  2. What is the meaning of the inside and outside functions when applying the chain rule?
  3. Can you find the derivative of P=8e0.5tP = 8e^{-0.5t}?
  4. How would the functions change if the outside function were a cube instead of a square?
  5. How would you apply these concepts to a real-world problem, like population growth?

Tip: When differentiating composite functions, always remember to multiply the derivative of the outside function by the derivative of the inside function (chain rule).

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Composite Functions
Exponential Functions
Polynomial Functions

Formulas

u(t) = 8t^2 - 5, y(u) = u^2
u(t) = -0.5t, P(u) = 8e^u
u(y) = y^6 + 7, C(u) = 5u

Theorems

Chain Rule for Differentiation

Suitable Grade Level

Grades 11-12