Math Problem Statement

The table below shows the ages of some trees and their corresponding heights. Find an exponential model for tree height as a function of age.

What height does your model predict for a 30-year-old tree?

Age (years) 8 13 18 Length (feet) 2.4 11.7 29.2

If you round your values when you write down the model, use at least three decimal places.

Solution

To find an exponential model for tree height as a function of age, we need to model the data in the form:

H(t)=aebtH(t) = a \cdot e^{bt}

where:

  • H(t)H(t) is the height of the tree as a function of age tt,
  • aa and bb are constants that we need to determine,
  • ee is the base of the natural logarithm.

Step 1: Set up equations based on given data points

We have three points from the table:

  • Age t1=8t_1 = 8, Height H1=2.4H_1 = 2.4,
  • Age t2=13t_2 = 13, Height H2=11.7H_2 = 11.7,
  • Age t3=18t_3 = 18, Height H3=29.2H_3 = 29.2.

Using the model H(t)=aebtH(t) = a \cdot e^{bt}, we get the following system of equations:

  1. 2.4=ae8b2.4 = a \cdot e^{8b}
  2. 11.7=ae13b11.7 = a \cdot e^{13b}
  3. 29.2=ae18b29.2 = a \cdot e^{18b}

Step 2: Solve the system of equations

2.1: Divide Equation 2 by Equation 1 to eliminate aa:

11.72.4=ae13bae8b11.72.4=e5b\frac{11.7}{2.4} = \frac{a \cdot e^{13b}}{a \cdot e^{8b}} \Rightarrow \frac{11.7}{2.4} = e^{5b} 4.875=e5b4.875 = e^{5b} Take the natural logarithm of both sides: ln(4.875)=5bb=ln(4.875)5\ln(4.875) = 5b \Rightarrow b = \frac{\ln(4.875)}{5}

2.2: Calculate bb:

b1.5845=0.3168b \approx \frac{1.584}{5} = 0.3168

2.3: Use Equation 1 to find aa:

Now substitute b0.3168b \approx 0.3168 into Equation 1: 2.4=ae8(0.3168)2.4 = a \cdot e^{8(0.3168)} 2.4=ae2.53442.4 = a \cdot e^{2.5344} 2.4a12.6142.4 \approx a \cdot 12.614 a2.412.6140.1903a \approx \frac{2.4}{12.614} \approx 0.1903

Step 3: Write the exponential model

Now that we have a0.1903a \approx 0.1903 and b0.3168b \approx 0.3168, the exponential model is: H(t)=0.190e0.317tH(t) = 0.190 \cdot e^{0.317t}

Step 4: Predict the height of a 30-year-old tree

Substitute t=30t = 30 into the model: H(30)=0.190e0.31730H(30) = 0.190 \cdot e^{0.317 \cdot 30} H(30)=0.190e9.51H(30) = 0.190 \cdot e^{9.51} H(30)0.19013461.8832557.757 feetH(30) \approx 0.190 \cdot 13461.883 \approx 2557.757 \text{ feet}

So, the model predicts that a 30-year-old tree will be approximately 2557.757 feet tall.


Would you like further details on the model or solution steps?

Related Questions:

  1. How would the model change if the tree growth rate decreased over time?
  2. How does an exponential model compare to a linear model for this data?
  3. What are other real-world phenomena that follow exponential growth?
  4. How can we verify the accuracy of the model for ages not given in the table?
  5. Can a logarithmic model provide a better fit for this data?

Tip:

Exponential models are commonly used for data that grows at an increasing rate, but always check if other models (e.g., logarithmic, polynomial) fit better!

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Math Problem Analysis

Mathematical Concepts

Exponential Growth
Algebra
Natural Logarithms

Formulas

Exponential model: H(t) = a * e^(bt)
Natural logarithm: ln(x)
Solving systems of equations

Theorems

Exponential Growth Function

Suitable Grade Level

Grades 10-12