Math Problem Statement

A function p estimates that there were 2,000 animals in a population in 1998. Each year from 1998 to 2010, the function estimates that the number of animals in this population increased by 3% of the number of animals in the population the previous year. Which equation defines this function, where p(x) is the estimated number of animals in the population x years after 1998?

Solution

The problem provides a population of animals starting at 2,000 in 1998. It mentions that the population increases by 3% each year from 1998 to 2010. The goal is to find the equation that defines the population p(x)p(x), where xx is the number of years after 1998.

The basic structure of an exponential growth model is: p(x)=p0(1+r)xp(x) = p_0 (1 + r)^x Where:

  • p0p_0 is the initial population (2000 animals),
  • rr is the rate of growth (3% or 0.03),
  • xx is the number of years after 1998.

Thus, the equation becomes: p(x)=2000(1+0.03)x=2000(1.03)xp(x) = 2000(1 + 0.03)^x = 2000(1.03)^x

Looking at the options, the correct one is C: p(x)=2000(1.03)xp(x) = 2000(1.03)^x

Would you like further explanation on exponential growth? Here are 5 questions that build on this concept:

  1. What happens if the population decreases by 3% each year instead of increasing?
  2. How would the equation change if the population started at a different number, say 5,000?
  3. What if the growth rate was 5% instead of 3%? How would the equation look?
  4. How can you calculate the population after a specific number of years, like 5 or 10 years?
  5. What is the difference between exponential growth and linear growth?

Tip: Exponential growth models are used in many real-world applications such as finance, population studies, and radioactive decay.

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Math Problem Analysis

Mathematical Concepts

Exponential Growth
Functions

Formulas

p(x) = p_0(1 + r)^x
p(x) = 2000(1.03)^x

Theorems

Exponential Growth Formula

Suitable Grade Level

Grades 9-12