Math Problem Statement

In 2016, a population of deer in an area was estimated to be 500 with a growth rate of 8% each year. Which of the following models estimates the population after t years?

Solution

The question in the image asks for the correct model to represent the population of deer growing at a rate of 8% per year, starting from an initial population of 500 in 2016.

To model population growth with a constant percentage increase, we use the exponential growth formula:

P(t)=P0(1+r)tP(t) = P_0 (1 + r)^t

Where:

  • P(t)P(t) is the population at time tt,
  • P0P_0 is the initial population (500 in this case),
  • rr is the growth rate (8% = 0.08),
  • tt is the number of years after the starting point (2016).

Thus, the equation becomes:

P(t)=500(1+0.08)t=500(1.08)tP(t) = 500 (1 + 0.08)^t = 500 (1.08)^t

The correct model is:

P(t)=500(1.08)tP(t) = 500 (1.08)^t

From the given choices, the third option ( P(t)=500(1.08)tP(t) = 500 (1.08)^t ) is the correct one.

Would you like more details or have any questions? Here are five related questions to expand on this concept:

  1. How would the model change if the growth rate were 5% instead of 8%?
  2. What is the population of deer after 5 years using the given model?
  3. How does the exponential growth formula differ from linear growth?
  4. Can exponential decay be modeled similarly? How would the formula change for a decay rate?
  5. What happens to the population if the growth rate is negative?

Tip: Always make sure to express percentage growth as a decimal in the exponential growth formula!

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Math Problem Analysis

Mathematical Concepts

Exponential Growth
Algebra

Formulas

P(t) = P_0 * (1 + r)^t

Theorems

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Suitable Grade Level

Grades 8-10