Math Problem Statement

If the rate of inflation is 3.9% per year, the future price p(t) (in dollars) of a certain item can be modeled by the following exponential function, where t is the number of years from today: p(t) = 1500(1.039)^t. Find the current price of the item and the price 10 years from today. Round your answers to the nearest dollar as necessary.

Solution

The problem describes an exponential growth model, where the future price p(t)p(t) of an item is given by:

p(t)=1500(1.039)tp(t) = 1500 \cdot (1.039)^t

1. Finding the Current Price (t=0t = 0):

Substitute t=0t = 0 into the equation:

p(0)=1500(1.039)0=15001=1500p(0) = 1500 \cdot (1.039)^0 = 1500 \cdot 1 = 1500

The current price of the item is $1500.


2. Finding the Price 10 Years From Today (t=10t = 10):

Substitute t=10t = 10 into the equation:

p(10)=1500(1.039)10p(10) = 1500 \cdot (1.039)^{10}

First, calculate (1.039)10(1.039)^{10}:

(1.039)101.456(1.039)^{10} \approx 1.456

Then:

p(10)=15001.4562184p(10) = 1500 \cdot 1.456 \approx 2184

The price 10 years from today is approximately $2184.


Final Answers:

  • Current Price: $1500
  • Price in 10 Years: $2184

Would you like further details or a step-by-step breakdown of the calculations?


Related Questions:

  1. How is exponential growth different from linear growth in pricing models?
  2. What would the price be 20 years from today using this model?
  3. How sensitive is this model to changes in the inflation rate?
  4. Could a compound interest formula explain the same concept here?
  5. What assumptions does this model make about inflation?

Tip: For exponential functions, small increases in the growth rate significantly impact long-term projections.

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Math Problem Analysis

Mathematical Concepts

Exponential Growth
Inflation Modeling
Substitution in Equations

Formulas

p(t) = 1500(1.039)^t

Theorems

Exponential Function Behavior

Suitable Grade Level

Grades 9-12