Math Problem Statement

The number of bacterial colonies doubles every 15 hours. If the number of the bacterial colonies in a petri dish is initially 90, what is the number of bacterial colonies on the 120th hour?

Solution

This problem involves exponential growth, where the number of bacterial colonies doubles every 15 hours. The general formula for exponential growth is given by:

N(t)=N0×2tTN(t) = N_0 \times 2^{\frac{t}{T}}

Where:

  • N(t)N(t) is the number of bacterial colonies at time tt.
  • N0N_0 is the initial number of bacterial colonies.
  • TT is the doubling time.
  • tt is the elapsed time.

For this problem:

  • N0=90N_0 = 90
  • T=15T = 15 hours
  • t=120t = 120 hours

Plugging in these values into the formula:

N(120)=90×212015N(120) = 90 \times 2^{\frac{120}{15}}

Simplifying the exponent:

12015=8\frac{120}{15} = 8

So:

N(120)=90×28N(120) = 90 \times 2^8

Calculating 282^8:

28=2562^8 = 256

Therefore:

N(120)=90×256=23040N(120) = 90 \times 256 = 23040

The number of bacterial colonies on the 120th hour is 23,040.

Would you like more details or have any questions? Here are some related questions you might find interesting:

  1. What would be the number of colonies after 45 hours?
  2. How would the formula change if the doubling time were 20 hours?
  3. What if the initial number of colonies were 150 instead of 90?
  4. How many hours would it take for the colonies to reach 1,000,000?
  5. What is the general form of the exponential growth formula for different growth rates?

Tip: When dealing with exponential growth, remember that doubling time directly affects the speed of increase. The smaller the doubling time, the faster the growth rate.

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Math Problem Analysis

Mathematical Concepts

Exponential Growth
Doubling Time
Algebra

Formulas

N(t) = N_0 * 2^(t/T)

Theorems

Exponential Growth Theorem

Suitable Grade Level

Grades 9-12