Math Problem Statement

After taking a dose of medication, the amount of medicine remaining in a person's bloodstream, in milligrams, after xx hours can be modeled by the function f, of, x, equals, 75, left parenthesis, 0, point, 8, 4, right parenthesis, to the power x , .f(x)=75(0.84) x . Find and interpret the given function values and determine an appropriate domain for the function. Round your answers to the nearest hundredth. Answer Attempt 1 out of 2

f, of, minus, 4, equalsf(−4)= , meaning hours after taking the dose, there are milligrams of medicine remaining in the person's bloodstream. This interpretation in the context of the problem. f, of, 42, equalsf(42)= , meaning hours after taking the dose, there are milligrams of medicine remaining in the person's bloodstream. This interpretation in the context of the problem. f, of, 10, point, 5, equalsf(10.5)= , meaning hours after taking the dose, there are milligrams of medicine remaining in the person's bloodstream. This interpretation in the context of the problem. Based on the observations above, it is clear that an appropriate domain for the function is .

Solution

Let's solve the problem step by step:

The function given is:

f(x)=75(0.84)xf(x) = 75(0.84)^x

where f(x)f(x) represents the amount of medicine remaining in milligrams after xx hours. We need to calculate specific values and interpret the results, as well as determine an appropriate domain for the function.


Step 1: Calculate f(4)f(-4)

f(4)=75(0.84)4f(-4) = 75(0.84)^{-4} Using the property of negative exponents, (ab=1/ab)(a^{-b} = 1/a^b): f(4)=751(0.84)4751.5916=119.37f(-4) = 75 \cdot \frac{1}{(0.84)^4} \approx 75 \cdot 1.5916 = 119.37 Interpretation: f(4)=119.37f(-4) = 119.37 means 4 hours before the medication was taken, there would be 119.37 mg of medicine in the bloodstream. This interpretation does not make sense in the context of the problem, as the function is only valid after the dose is taken.


Step 2: Calculate f(42)f(42)

f(42)=75(0.84)42f(42) = 75(0.84)^{42} f(42)75(0.000037)0.0028f(42) \approx 75 \cdot (0.000037) \approx 0.0028 Interpretation: f(42)=0.0028f(42) = 0.0028 means 42 hours after taking the medication, approximately 0.0028 mg of medicine remains in the bloodstream. This interpretation is valid in the context of the problem, but the amount of medicine is effectively negligible.


Step 3: Calculate f(10.5)f(10.5)

f(10.5)=75(0.84)10.5f(10.5) = 75(0.84)^{10.5} f(10.5)750.235117.63f(10.5) \approx 75 \cdot 0.2351 \approx 17.63 Interpretation: f(10.5)=17.63f(10.5) = 17.63 means 10.5 hours after taking the medication, approximately 17.63 mg of medicine remains in the bloodstream. This interpretation makes sense and is consistent with the function.


Step 4: Determine the Domain

The domain of the function should correspond to meaningful xx-values in the context of the problem. Since xx represents the number of hours after taking the dose, the domain must start at x=0x = 0 (when the dose is taken) and extend indefinitely into the future. However, practically, the function is only meaningful as long as f(x)>0f(x) > 0, which happens for x0x \geq 0.

Thus, the appropriate domain is:

x0x \geq 0


Final Answer

  1. f(4)=119.37f(-4) = 119.37: This interpretation does not make sense in the context of the problem.
  2. f(42)=0.0028f(42) = 0.0028: This interpretation makes sense, but the medicine is effectively negligible at this point.
  3. f(10.5)=17.63f(10.5) = 17.63: This interpretation makes sense and is realistic.
  4. Domain: x0x \geq 0.

Follow-Up Questions

  1. What would f(20)f(20) represent in the context of the problem?
  2. How does the value of f(x)f(x) change as xx increases?
  3. What is the half-life of the medicine based on this function?
  4. Why does the domain exclude negative values of xx?
  5. How could this function be used to estimate when the medication becomes ineffective?

Tip: When analyzing exponential decay, always consider the initial value and the base to determine how quickly the quantity decreases.

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Math Problem Analysis

Mathematical Concepts

Exponential Decay
Functions and Their Domains
Function Evaluation

Formulas

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Theorems

Properties of Exponents

Suitable Grade Level

Grades 9-12