Math Problem Statement
Solution
Let'sLet's work through the tasks in go the image.
Task 1: Find the values of the expressions
throughFor the the first expressions part: 1 in. image -:
Solution1:
(
3^24. + ( b3) \quad 12 : 12 ^)
3\ ).
-
- Calculate Solution each term separately: : - \( 312^ :4 =12 =81 1 \ )
- Task ( 3^32 =: Simpl27ify\ the)
expressions
For - the Add them together second part: : 1 . - ( ( a3)^ \4quad + \ left3(^ a3 =^{-3 81} + \27 =right )^4 \108cd\ot)
a ^{22} ) So, - the Solution result: of the \ first[ part is \ left108( a.
^{-23.} ** \Expressionright 2**: Simplify a) \left(a^{-3}^right4)^ = a^{-12}4 \ \quadcd \ottext a{^{and22 thus},).
} \ -quad Use a the^{- power12 rule} \ ((cdaot^ am^{)^22n} = = a a^{^{m22 \ -cd ot12 n}}\ =): a ^{ -10 } (\ left ]
- Answer:
- b)(a \quad 0.4x^6^{- y3^{-}\8right})^ \4cd = a^{-3 \cdot 4} = a^{-12}
- Combine powersot: (50ax^{-^{-125}} \ ycd^ot9 a ^{) 22 } - = Solution a: ^{- 12 \ +[ 22 }0 =.4 \ acd^{10ot})
50 = 20 The simplified form for, this \quad expression is x ^6^{-5.
}3 = x. ^{Expression6 3 - :5} = Simpl x,ify \quad y (b) 0.4^{-x8^}6 \ ycd^{-ot8 y^}9 = \ ycd^{ot9 -50 x^{-5} y^98} =\ y ).
\ ]
-
- Simpl Finalify answer the: constants ( first20:
- (xy0 .)
4Would \ you like further details on anycdot 50 = part20\ of these) solutions , or do - you have For ( specific questionsx?
###)- Relatedterms: Questions
-
(x How^ would6 the \ calculationscd changeot if x the^{- ex5ponents} were = modified x? ^{26. - What 5} = x^1 are = x some\ properties) of ex ponents that simplify - expressions For - liketerms these:? (3y.^{- Can8 you} apply \ similarcd steps to simplify expressions with different bases? 4ot y^.9 How = y^{- would8 you + approach if9 there} were variables in the = y^1 = y)
So, the divisor simplified as form well is? 5(.20 Whatxy role\ does) the.
order---
ofWould operations play in you simplification?
like Tip further:
Remember details, when working on with any exponents of, applying these the solutions power?
ruleHere are \ some(( followa-up^ questionsm related)^ ton these = problems a:
^{1m. \cd Howot n}) and product would the solution change if rule we ( werea given different exponents? ^2m \cdot a^n. What rules = apply a when simplifying^{m expressions+n with negative}) exponents can? simplify3 complex. expressions How significantly. would we simplify expressions with fractional exponents? 4. Can we apply these exponent rules to variables with different bases? 5. How does the distributive property differ from the rules for simplifying exponents?
Tip: When multiplying terms with the same base, remember to add the exponents.
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Math Problem Analysis
Mathematical Concepts
Exponentiation
Simplification of expressions
Properties of exponents
Formulas
a^m * a^n = a^(m+n)
(a^m)^n = a^(m*n)
a^0 = 1
Theorems
Laws of Exponents
Suitable Grade Level
Grades 8-10
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