The probabilities that a patient will have 0, 1, 2, or 3 medical tests performed on
entering a hospital are !
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The probabilities provided for a patient having 0, 1, 2, or 3 medical tests upon entering a hospital are:

- Probability of 0 tests: $ \frac{1}{8} $
- Probability of 1 test: $ \frac{3}{8} $
- Probability of 2 tests: $ \frac{3}{8} $
- Probability of 3 tests: $ \frac{1}{8} $

These probabilities form a discrete probability distribution, which can be used to compute several important statistics such as the expected number of tests, variance, and standard deviation.

### 1. Expected Value (Mean)
The expected value $ E(X) $ of the number of tests $ X $ can be calculated using the formula:

\[
E(X) = \sum_{x} x \cdot P(x)
\]

Where $ x $ is the number of tests, and $ P(x) $ is the probability associated with $ x $.

So, for this case:

\[
E(X) = 0 \cdot \frac{1}{8} + 1 \cdot \frac{3}{8} + 2 \cdot \frac{3}{8} + 3 \cdot \frac{1}{8}
\]

\[
E(X) = 0 + \frac{3}{8} + \frac{6}{8} + \frac{3}{8} = \frac{12}{8} = 1.5
\]

### 2. Variance
The variance $ \text{Var}(X) $ is calculated using:

\[
\text{Var}(X) = E(X^2) - [E(X)]^2
\]

First, let's calculate $ E(X^2) $:

\[
E(X^2) = 0^2 \cdot \frac{1}{8} + 1^2 \cdot \frac{3}{8} + 2^2 \cdot \frac{3}{8} + 3^2 \cdot \frac{1}{8}
\]

\[
E(X^2) = 0 + \frac{3}{8} + \frac{12}{8} + \frac{9}{8} = \frac{24}{8} = 3
\]

Now, the variance is:

\[
\text{Var}(X) = E(X^2) - [E(X)]^2 = 3 - (1.5)^2 = 3 - 2.25 = 0.75
\]

### 3. Standard Deviation
The standard deviation $ \sigma $ is the square root of the variance:

\[
\sigma = \sqrt{\text{Var}(X)} = \sqrt{0.75} \approx 0.866
\]

Would you like more details on any of these calculations?

Here are some related questions:

1. How does the expected number of tests change with different probability distributions?
2. What is the importance of variance in this context?
3. How would the calculations change if the probabilities were not equally distributed?
4. How can we interpret the standard deviation in a medical context?
5. How would you calculate the probability of having more than 1 test performed?

**Tip:** The expected value tells you the average outcome in the long run if the scenario (in this case, testing) is repeated many times.

The probabilities that a patient will have 0, 1, 2, or 3 medical tests performed on entering a hospital are $ \frac{1}{8} $, $ \frac{3}{8} $, $ \frac{3}{8} $, and $ \frac{1}{8} $, respectively.

Explore how to calculate the expected value, variance, and standard deviation of the number of medical tests performed on a patient. Using the probabilities of 0, 1, 2, and 3 tests, this detailed solution covers key concepts in probability and statistics, suitable for students in Grades 10-12.

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