Math Problem Statement

What is the expected value of the probability distribution of the discrete random variable X?

Solution

To find the expected value μ\mu of a discrete random variable XX, we use the formula:

μ=E(X)=(xP(X=x))\mu = E(X) = \sum \big(x \cdot P(X = x)\big)

Here, each value of X=xX = x is multiplied by its corresponding probability P(X=x)P(X = x), and the results are summed up.

From the table:

xxP(X=x)P(X = x)
220.070.07
440.190.19
660.250.25
880.110.11
10100.070.07
12120.300.30
14140.010.01

Now, compute xP(X=x)x \cdot P(X = x) for each pair and sum them:

E(X)=2(0.07)+4(0.19)+6(0.25)+8(0.11)+10(0.07)+12(0.30)+14(0.01)E(X) = 2(0.07) + 4(0.19) + 6(0.25) + 8(0.11) + 10(0.07) + 12(0.30) + 14(0.01)

Let's calculate this. Values of x and their corresponding probabilities x_values = [2, 4, 6, 8, 10, 12, 14] probabilities = [0.07, 0.19, 0.25, 0.11, 0.07, 0.30, 0.01]

Calculating the expected value

expected_value = sum(x * p for x, p in zip(x_values, probabilities)) expected_valueThe expected value μ\mu of the probability distribution is:

μ=7.72\mu = 7.72

The correct option is:

μ=7.72\mu = 7.72.

Would you like further explanations, or have any additional questions about this topic?

Here are 5 related questions to explore further:

  1. How do you calculate the variance of a discrete random variable?
  2. What does the expected value of a random variable represent in probability theory?
  3. How is the expected value applied in real-life scenarios like finance or insurance?
  4. What is the relationship between expected value and the mean of a dataset?
  5. How would the probabilities or outcomes being incorrect affect the expected value?

Tip: Always ensure the probabilities in a discrete probability distribution add up to 1. This helps verify correctness!

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Math Problem Analysis

Mathematical Concepts

Probability
Expected Value
Discrete Random Variables

Formulas

Expected Value formula: μ = E(X) = Σ(x * P(X = x))

Theorems

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Suitable Grade Level

Grades 10-12