Math Problem Statement

A lottery has a grand prize of $1,000,000, 4 runner-up prizes of $50,000 each, 14 third-place prizes of $5,000 each, and 28 consolation prizes of $1,000 each. If a 13 million tickets are sold for $1 each, and the probability of any ticket winning is the same as that of any other winning, find the expected return on a $1 ticket. (Round your answer to the nearest cent.)

Solution

To find the expected return on a $1 lottery ticket, we calculate the expected value of the winnings for a single ticket. This involves summing up the products of each prize amount and its associated probability.

Step 1: Define the variables

  • Total tickets: N=13,000,000N = 13,000,000
  • Ticket cost: C=1C = 1 dollar
  • Prizes:
    • Grand prize: 1×1,000,0001 \times 1,000,000
    • Runner-up prizes: 4×50,0004 \times 50,000
    • Third-place prizes: 14×5,00014 \times 5,000
    • Consolation prizes: 28×1,00028 \times 1,000

Step 2: Calculate the probability of each prize

The probability of winning a specific prize is: P(prize)=number of prizesNP(\text{prize}) = \frac{\text{number of prizes}}{N}

Probabilities for each prize:

  • Grand prize: P(1,000,000)=113,000,000P(1,000,000) = \frac{1}{13,000,000}
  • Runner-up prize: P(50,000)=413,000,000P(50,000) = \frac{4}{13,000,000}
  • Third-place prize: P(5,000)=1413,000,000P(5,000) = \frac{14}{13,000,000}
  • Consolation prize: P(1,000)=2813,000,000P(1,000) = \frac{28}{13,000,000}

Step 3: Calculate the expected value of winnings

The expected value EE is given by: E=(prize amount×probability of winning)E = \sum (\text{prize amount} \times \text{probability of winning})

Substituting the values: E=(1,000,000×113,000,000)+(50,000×413,000,000)+(5,000×1413,000,000)+(1,000×2813,000,000)E = \left(1,000,000 \times \frac{1}{13,000,000}\right) + \left(50,000 \times \frac{4}{13,000,000}\right) + \left(5,000 \times \frac{14}{13,000,000}\right) + \left(1,000 \times \frac{28}{13,000,000}\right)

Simplify each term:

  • Grand prize: 1,000,000×113,000,000=1,000,00013,000,000=0.076921,000,000 \times \frac{1}{13,000,000} = \frac{1,000,000}{13,000,000} = 0.07692
  • Runner-up prize: 50,000×413,000,000=200,00013,000,0000.0153850,000 \times \frac{4}{13,000,000} = \frac{200,000}{13,000,000} \approx 0.01538
  • Third-place prize: 5,000×1413,000,000=70,00013,000,0000.005385,000 \times \frac{14}{13,000,000} = \frac{70,000}{13,000,000} \approx 0.00538
  • Consolation prize: 1,000×2813,000,000=28,00013,000,0000.002151,000 \times \frac{28}{13,000,000} = \frac{28,000}{13,000,000} \approx 0.00215

Sum these values: E0.07692+0.01538+0.00538+0.00215=0.09983E \approx 0.07692 + 0.01538 + 0.00538 + 0.00215 = 0.09983

Step 4: Subtract the cost of the ticket

The net expected return is: Enet=EC=0.099831=0.90017E_{\text{net}} = E - C = 0.09983 - 1 = -0.90017

Final Answer:

The expected return on a $1 lottery ticket is approximately $0.90-\$0.90.


Would you like a detailed breakdown of any part? Here are 5 related questions:

  1. How is the probability of winning calculated for each prize?
  2. Can you explain why the expected return is negative?
  3. How would the expected return change if fewer tickets were sold?
  4. What does the expected value tell us about playing the lottery?
  5. How do the probabilities affect the overall fairness of the lottery?

Tip: The expected value reflects the average outcome over a large number of plays. It does not guarantee individual results!

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Math Problem Analysis

Mathematical Concepts

Probability
Expected Value
Basic Arithmetic Operations

Formulas

Probability of event = (Number of favorable outcomes) / (Total outcomes)
Expected Value = Sum of (Prize Amount × Probability of Winning)

Theorems

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Suitable Grade Level

Grades 10-12