To expand the expression \((x + 3)^3\), we can use the binomial theorem or apply the cube formula directly.

The expansion of \((a + b)^3\) is given by:

\[
(a + b)^3 = a^3 + 3a^2b + 3ab^2 + b^3
\]

For \((x + 3)^3\), let \(a = x\) and \(b = 3\). Applying the formula:

\[
(x + 3)^3 = x^3 + 3(x^2)(3) + 3(x)(3^2) + 3^3
\]

Simplifying each term:

\[
(x + 3)^3 = x^3 + 9x^2 + 27x + 27
\]

So, the expanded form of \((x + 3)^3\) is:

\[
x^3 + 9x^2 + 27x + 27
\]

Would you like further details or have any questions?

Here are 5 related questions to consider:
1. How would you expand \((x - 3)^3\)?
2. What is the general formula for \((x + y)^n\) using the binomial theorem?
3. Can you factor the expanded form of \((x + 3)^3\)?
4. How would the expansion change if the exponent was 4, i.e., \((x + 3)^4\)?
5. How can you use this expansion to solve cubic equations?

**Tip:** When expanding binomials, pay attention to the powers of each term and the binomial coefficients.

Explore the step-by-step expansion of (x + 3)^3 using the binomial theorem. This problem covers key algebraic concepts like polynomials and binomial expansion, suitable for students in Grades 9-11.

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